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Old February 9th, 2004, 12:40 PM
gb gb is offline
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Default Matching of attribute values

Hi,

I have a basic question of matching of attribute values:

If I have a document fragment:

<model>

 <enum name="ABC">
   <enunMember name="member1">
      <value>0</value>
  </enumMember>
   <enunMember name="member2">
      <value>1</value>
  </enumMember>
 </enum>

 <enum name="XYZ">
   <enumMember name="member5">
      <value>20</value>
  </enumMember>
   <enumMember name="member7">
      <value>22</value>
  </enumMember>
 </enum>

 <class>
  <attribute name="attr1">
   <datatype>
     <enumRef name= "ABC">
        <value>20</value>
     </enumRef>
   </datatype>
  </attribute>
 </class>

</model>

---------------------------------------------------------------------------------------------------

When processing an 'attribute', I want to dump out the type information of the referenced "enum". I am struggling with the syntax to find the related "enum" from the "enumRef" name in "attribute".

I'm using the following:

<xsl:template match="enumRef">
        <xsl:value-of select="@name"/>

    <xsl:apply-templates select="//enum[@name ='ABC']">
    <xsl:apply-templates select="//enum[@name='{attribute::@name}' ]">

        </xsl:apply-templates>
</xsl:template>


What is the correct syntax to match an element using an attribute ["name" in this case] generically?

many thanks,
gb
 
Old February 9th, 2004, 05:25 PM
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Default

I think you needf to use current node:
Code:
<xsl:template match="enumRef">
<xsl:apply-templates select="//enum[@name = current()/@name ]"/>    </xsl:template>
--

Joe
 
Old February 10th, 2004, 04:12 AM
gb gb is offline
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Default

Joe,

Thanks for this.

regards,
gb




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