In xslt how do I calculate the xml's person height to show in inches?

winkimjr2 · August 13th, 2014, 11:25 AM

I have the following xml element. I want to calculate this height in xslt so it displays as 65 inches. I know I have to multiply 5 feet by 12 and then add 5 inches. But I am not sure how to do it.

Code:

<HeightFeet>5</HeightFeet>
<HeightInches>5</HeightInches>

Here is my xslt code

Code:

<nc:PersonHeightMeasure>
		<nc:MeasureText>
		    <xsl:value-of select="HeightFeet"/>
		    <xsl:value-of select="HeightInches"/>
		</nc:MeasureText>
		<nc:MeasureUnitText>
		    <xsl:text>inches</xsl:text>
		</nc:MeasureUnitText>
			<nc:LengthUnitCode>
				<xsl:text>INH</xsl:text>
			</nc:LengthUnitCode>
	</nc:PersonHeightMeasure>

This xslt displays the following which is not what I want.

Code:

<nc:PersonHeightMeasure>
		<nc:MeasureText>55</nc:MeasureText>
		<nc:MeasureUnitText>inches</nc:MeasureUnitText>
		<nc:LengthUnitCode>INH</nc:LengthUnitCode>
	</nc:PersonHeightMeasure>

mhkay · August 13th, 2014, 11:46 AM

Ah yes, feet and inches - I remember learning about them in history lessons...

In XPath it's

Code:

<xsl:value-of select="HeightFeet * 12 + HeightInches"/>

(Did you know that these forums are provided for readers of Wrox books to ask any questions that they can't find answered in the books? I find it a little difficult to believe that you have read very far to be asking a question like this.)

winkimjr2 · August 13th, 2014, 04:45 PM

I did solve this on my own but thank you for the response.

winkimjr2 · August 13th, 2014, 04:48 PM

I know that and I do have Professional Visual Basic 2010 and .NET 4.0 paper book that I bought.