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Old September 26th, 2014, 03:44 PM
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Default Element not displaying the right out put

I have a node with two elements for date of birth. I only want to display the element with <DateOfBirth Current ="true">.
The problem is that my xslt is displaying the first element even if it does not have Current="true".
How can I change my xslt to display the correct dateofbirth with the current =true?

My XML code

Code:
<Party ID="16547750" InternalPartyID="1614450882">
   <DateOfBirth>08/31/1979</DateOfBirth>
   <DateOfBirth Current="true">08/31/1980</DateOfBirth>
</Party>
My XSLT code. How can I change it to display correct dateofbirth?

Code:
<ext:PersonBirthDate>
     <xsl:choose>
	<xsl:when test="DateOfBirth">
        <xsl:attribute name="ext:approximateDateIndicator">false</xsl:attribute>
	<xsl:attribute name="ext:currentIndicator">true</xsl:attribute>  
	<xsl:value-of select="mscef:formatDate(string(DateOfBirth))"/>
	</xsl:when>
	<xsl:when test="ApproximateDOB">
	<xsl:attribute name="ext:approximateDateIndicator">true</xsl:attribute>
	<xsl:attribute name="ext:currentIndicator">true</xsl:attribute>
	<xsl:value-of select="mscef:formatDate(string(ApproximateDOB))"/>
	</xsl:when>
     </xsl:choose>
</ext:PersonBirthDate>
The out put display by this code is wrong
Code:
<ext:PersonBirthDate ext:approximateDateIndicator="false" ext:currentIndicator="true">1979-08-31</ext:PersonBirthDate>
The correct out put should be
Code:
<ext:PersonBirthDate ext:approximateDateIndicator="false" ext:currentIndicator="true">1980-08-31</ext:PersonBirthDate>
 
Old September 26th, 2014, 04:03 PM
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Default

Change both occurrences of DateOfBirth in your code to DateOfBirth[@Current='true']
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Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference





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