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April 28th, 2018, 10:31 AM
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removing duplicate data in xml not displaying correct result
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="kMapping" match="Registration" use="Country"/>
<xsl:template match="@* | node()" name="Copy">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Registration[generate-id() = generate-id(key('kMapping', Country)[1])]">
<xsl:call-template name="Copy"/>
</xsl:template>
<xsl:template match="Registration"/>
</xsl:stylesheet>
XML Code Input file
=================
<FundsXML> <Funds> <Fund> <Name>Fund11111 </Name> <FundFacts> <KeyFacts> <Registration> <Country>AT</Country> </Registration> <Registration> <Country>AT</Country> </Registration> <Registration> <Country>BE</Country> </Registration> <Registration> <Country>BE</Country> </Registration> <Registration> <Country>BE</Country> </Registration> </KeyFacts> </FundFacts> <Name>Fund22222 </Name> <SecurityCodes> <CountrySecurityCode> <CountryCode>DE</CountryCode> </CountrySecurityCode> </SecurityCodes> <FundFacts> <KeyFacts> <Registration> <Country>AE</Country> </Registration> <Registration> <Country>AT</Country> </Registration> <Registration> <Country>AT</Country> </Registration> <Registration> <Country>BE</Country> </Registration> <Registration> <Country>BE</Country> </Registration> <Registration> <Country>BE</Country> </Registration> <Registration> <Country>PT</Country> </Registration> </KeyFacts> </FundFacts> </Fund> </Funds> </FundsXML>
Desired output
Need country code to be displayed once per fund11111 and fund22222
<FundsXML> <Funds> <Fund> <Name>Fund11111 </Name> <FundFacts> <KeyFacts> <Registration> <Country>AT</Country> </Registration> <Registration> <Country>BE</Country> </Registration> </KeyFacts> </FundFacts> <Name>Fund22222 </Name> <FundFacts> <KeyFacts> <Registration> <Country>AE</Country> </Registration> <Registration> <Country>AT</Country> </Registration> <Registration> <Country>BE</Country> </Registration> <Registration> <Country>PT</Country> </Registration> </KeyFacts> </FundFacts> </Fund> </Funds> </FundsXML>
The code is displayed singlecountry record for first fund only and removing country value records which are present in Fund22222
Output displayed by above XSLT
==============================
<FundsXML> <Funds> <Fund> <Name>Fund11111 </Name> <FundFacts> <KeyFacts> <Registration> <Country>AT</Country> </Registration> <Registration> <Country>BE</Country> </Registration> </KeyFacts> </FundFacts> <Name>Fund22222 </Name> <FundFacts> <KeyFacts> <Registration> <Country>PT</Country> </Registration> </KeyFacts> </FundFacts> </Fund> </Funds> </FundsXML>
Any help will be much appreciated
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April 28th, 2018, 10:52 AM
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Are you really restricted to XSLT 1.0?
In XSLT 2 you could use match="Registration[generate-id() = generate-id(key('kMapping', Country, ancestor::Fund)[1])]" or use for-each-group
__________________
Martin Honnen
Microsoft MVP (XML, Data Platform Development) 2005/04 - 2013/03
My blog
Last edited by Martin Honnen; April 28th, 2018 at 11:27 AM..
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April 28th, 2018, 11:41 AM
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Quote:
Originally Posted by Martin Honnen
Are you really restricted to XSLT 1.0?
In XSLT 2 you could use match="Registration[generate-id() = generate-id(key('kMapping', Country, ancestor::Fund)[1])]" or use for-each-group
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Hi Martin
thanks for the information
Not really restricted with XSLT 1.0
Could use 2.0 version
Let me check on it and revert back
thank you |
April 28th, 2018, 11:57 AM
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Quote:
Originally Posted by Martin Honnen
Are you really restricted to XSLT 1.0?
In XSLT 2 you could use match="Registration[generate-id() = generate-id(key('kMapping', Country, ancestor::Fund)[1])]" or use for-each-group
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---------------------------------
HI Martin
I have used following code for the xml filtering on duplicate. but out of 4 countries its displaying 2 countries which are duplicate per Fund
<FundFacts>
<KeyFacts>
<Registration>
<Country>AE</Country>
</Registration>
<Registration>
<Country>AE</Country>
</Registration>
<Registration>
<Country>AT</Country>
</Registration>
<Registration>
<Country>AT</Country>
</Registration>
<Registration>
<Country>TW</Country>
</Registration>
<Registration>
<Country>ZA</Country>
</Registration>
</KeyFacts>
</FundFacts>
<FundFacts>
<KeyFacts>
<Registration>
<Country>AE</Country>
</Registration>
<Registration>
<Country>AT</Country>
</Registration>
</KeyFacts>
</FundFacts>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="2.0" encoding="UTF-8" indent="yes" omit-xml-declaration="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="cc" match="Registration" use="Country"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Registration[generate-id() = generate-id(key('cc', Country, ancestor::Fund)[1])]"
/>
</xsl:stylesheet>
Last edited by virgosaggi; April 28th, 2018 at 12:02 PM..
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April 28th, 2018, 12:06 PM
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My suggestion was to simply change that one match pattern to the one I posted, the rest of your code did not need any change but need to be kept. So don't change the key declaration and simply edit that match pattern as suggested.
__________________
Martin Honnen
Microsoft MVP (XML, Data Platform Development) 2005/04 - 2013/03
My blog
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April 28th, 2018, 12:17 PM
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Quote:
Originally Posted by Martin Honnen
My suggestion was to simply change that one match pattern to the one I posted, the rest of your code did not need any change but need to be kept. So don't change the key declaration and simply edit that match pattern as suggested.
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Hi Martin
All I did based on suggestion was below code nothing else changed
<xsl:template match="Registration[generate-id() = generate-id(key('cc', Country, ancestor::Fund)[1])]"
/>
</xsl:stylesheet>
Sample Data:
================
<FundsXML>
<Funds>
<Fund>
<Name>Fund111111</Name>
<FundFacts>
<KeyFacts>
<Registration>
<Country>AE</Country>
</Registration>
<Registration>
<Country>AE</Country>
</Registration>
<Registration>
<Country>AT</Country>
</Registration>
<Registration>
<Country>AT</Country>
</Registration>
<Registration>
<Country>TW</Country>
</Registration>
<Registration>
<Country>ZA</Country>
</Registration>
</KeyFacts>
</FundFacts>
</Fund>
</Funds>
<Fund>
<Name>Fund222222</Name>
<FundFacts>
<KeyFacts>
<Registration>
<Country>AE</Country>
</Registration>
<Registration>
<Country>AE</Country>
</Registration>
<Registration>
<Country>IT</Country>
</Registration>
<Registration>
<Country>IT</Country>
</Registration>
<Registration>
<Country>TA</Country>
</Registration>
<Registration>
<Country>ZA</Country>
</Registration>
</KeyFacts>
</FundFacts>
</Fund>
</FundsXML>
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April 28th, 2018, 12:39 PM
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I wanted you to change the other match pattern.
__________________
Martin Honnen
Microsoft MVP (XML, Data Platform Development) 2005/04 - 2013/03
My blog
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April 28th, 2018, 12:52 PM
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Quote:
Originally Posted by Martin Honnen
I wanted you to change the other match pattern.
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Hello Martin
Fund is the main pattern to filter out the distinct country code fund wise
thank you |
April 28th, 2018, 01:07 PM
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Quote:
Originally Posted by Martin Honnen
I wanted you to change the other match pattern.
|
Hi Martin
It seem to work with the suggestion you gave
I added NOT clause
<xsl:template match="Registration[not( generate-id() = generate-id(key('cc', Country, ancestor::Fund)[1]))]"
/>
</xsl:stylesheet>
checking on dataset |
April 30th, 2018, 07:47 AM
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Quote:
Originally Posted by virgosaggi
Hi Martin
It seem to work with the suggestion you gave
I added NOT clause
<xsl:template match="Registration[not( generate-id() = generate-id(key('cc', Country, ancestor::Fund)[1]))]"
/>
</xsl:stylesheet>
checking on dataset
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Hi Martin
Using the suggestions above it worked in xmlspy
But when I am trying to run based on a wrapper code it’s failing saying y needs two arguments to the generate-id(key())
Any suggestions
Thank you |
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