fail login sql database...

junghyun baek · November 15th, 2005, 08:24 PM

OS : windows server 2003
DB : SQL server 2000

Would you help me?

case1

    string conn = "server=localhost; database=Dotnet; uid=sa; pwd=;";
    SqlConnection connection = new SqlConnection(conn);
    connection.Open();

This case1 is occurred Exception(System.InvalidCastException)

[InvalidCastException: ÃÃ¶ÃÂ¤ÃÃ ÃÂ³Â½ÂºÃÂ®Â°Â¡ ÃÃÂ¸Ã¸ÂµÃÂ¾ÃºÂ½ÃÂ´ÃÂ´Ã.]
   ASP.control_test_aspx.Setmyname(Object src, EventArgs e) +133
   System.Web.UI.WebControls.Button.OnClick(EventArgs e) +108
   System.Web.UI.WebControls.Button.System.Web.UI.IPo stBackEventHandler.RaisePostBackEvent(String eventArgument) +57
   System.Web.UI.Page.RaisePostBackEvent(IPostBackEve ntHandler sourceControl, String eventArgument) +18
   System.Web.UI.Page.RaisePostBackEvent(NameValueCol lection postData) +33
   System.Web.UI.Page.ProcessRequestMain() +1277

case2

    string conn = "server=localhost; database=Northwind; uid=sa; pwd=;";
    SqlConnection connection = new SqlConnection(conn);
    connection.Open();

This case2 is not occurred Exception. Login success.

Q1. I don't understand above state. Why case1 have CastExeption?

case3

    string conn = "server=localhost; database=Northwind; uid=Administrator; pwd=star_3327;";
    SqlConnection connection = new SqlConnection(conn);
    connection.Open();

This case3 can't login sql server(System.Data.SqlClient.SqlException).

[SqlException: 'Administrator' Â»Ã§Â¿Ã«ÃÃÂ°Â¡ Â·ÃÂ±ÃÃÃÃÃÃÃ¶ Â¸Ã¸ÃÃÂ½ÃÂ´ÃÂ´Ã.]
   System.Data.SqlClient.ConnectionPool.GetConnection (Boolean& isInTransaction) +472
   System.Data.SqlClient.SqlConnectionPoolManager.Get PooledConnection(SqlConnectionString options, Boolean& isInTransaction) +372
   System.Data.SqlClient.SqlConnection.Open() +384
   ASP.control_test_aspx.Setmyname(Object src, EventArgs e) +72
   System.Web.UI.WebControls.Button.OnClick(EventArgs e) +108
   System.Web.UI.WebControls.Button.System.Web.UI.IPo stBackEventHandler.RaisePostBackEvent(String eventArgument) +57
   System.Web.UI.Page.RaisePostBackEvent(IPostBackEve ntHandler sourceControl, String eventArgument) +18
   System.Web.UI.Page.RaisePostBackEvent(NameValueCol lection postData) +33
   System.Web.UI.Page.ProcessRequestMain() +1277

Q2. Why case3 can't login?

subhendude · November 17th, 2005, 11:18 AM

I think there is a SQL Server Internal error. Just see,case 1 and case 2 is custom created but case 2 is automatically created when u installed SQL Server.
I have kept ur query in mind and give u reply as soon as possible. But I think it is internal error. Check the same think in wizard basis that ships in VS.NET and check the "TEST CONNECTION".

Subhendu De
Software Developer
New Delhi

Subhendu De

junghyun baek · November 22nd, 2005, 08:20 PM

when we use ASP in same state, we success login.

This is ASP source code

DbConn.asp
<%
Function DbOpen(objCon)
    set objCon = server.createObject("ADODB.Connection")
    objCon.Open "Provider=SQLOLEDB.1;Password=sa_3327;Persist Security Info=True;User ID=sa;Initial Catalog=Dotnet;Data Source=star"
End Function

Function DbClose(objCon)
    objCon.close
    set objCon = nothing
End Function
%>

test.asp

<%
name=request("name")
address=request("name")
telephone=request("telephone")
if name <> "" then
    Call DbOpen(Conn)
    Conn.BeginTrans
    ON ERROR RESUME NEXT

    sqlstr="insert into test_info (name,address,telephone) values "
    sqlstr=sqlstr&"('"&name&"','"&address&"','"&teleph one&"')"
    Conn.Execute(sqlstr)
    Error_cnt=Error_cnt+Conn.Errors.Count

    if Error_cnt = 0 then
        Conn.CommitTrans
        Response.write "<script language=JavaScript>alert('ÂµÃ®Â·ÃÂµÃÂ¾ÃºÂ½ÃÂ´Ã Â´Ã.');</script>"
    Else
        Conn.RollbackTrans
        Response.write "<script language=JavaScript>alert('\n Database Â¿Â¡Â·Â¯!!');history.back();</script>"
    End If

    Call DBClose(Conn)
end if
%>
<html>
<body>
<form name="theForm" action="test.asp" method="post">
<table>
<tr>
    <td>ÃÃÂ¸Â§</td>
    <td><input type="text" size="10" name="name" value=""></td>
</tr>
<tr>
    <td>ÃÃÂ¼Ã</td>
    <td><input type="text" size="50" name="address" value=""></td>
</tr>
<tr>
    <td>Â¿Â¬Â¶Ã´ÃÂ³</td>
    <td><input type="text" size="20" name="telephone" value=""></td>
</tr>
<tr>
    <td colspan=2 align=center><input type="submit" size="20" name="btn" value="ÂµÃ®Â·Ã"></td>
</tr>
</table>
</form>
</body>
</html>