Hello:
From a web form I’m sending to execute a function contained into a class, code in web form is:

bool que = WUC_CreDes.Class1.Hay_PostBack(this, w1,w1cx, w1ID, w2, w2cx, w2ID);

In class code is:

public static bool Hay_PostBack(WUC_CreDes.WebForm1 parent1, string w1,
            string w1cx,
            string w1ID,
            string w2,
            string w2cx,
            string w2ID)
        {
            string cual = "";
            cual = HttpContext.Current.Session["par1"].ToString();
            parent1.Example.Controls.Clear();
            if(cual == w1)
            {
                Control control = parent1.Page.LoadControl(w1cx);
                control.ID = w1ID;
                parent1.Example.Controls.Add(control);
            }
            else
            {
                Control control = parent1.Page.LoadControl(w2cx);
                control.ID = w2ID;
                parent1.Example.Controls.Add(control);
            }
            return false;
        }

As you can see, I’m sending to function container into class my WebForm1 to create in function WUC dynamically created.

Thinking in a second web form, let us say, WebForm2, if within it I send to execute my function:

bool que = WUC_CreDes.Class1.Hay_PostBack(this, w1,w1cx, w1ID, w2, w2cx, w2ID);

How can I do to function Hay_PostBack, above mentioned work also for WebForm2 What I need to change because first parameter is WUC_CreDes.Web Form1 parent1?
I’ll thank your answers.

Greetings.

A.L.

El Hombre que tiene Amigos ha de mostrarse Amigo

__________________
El Hombre que tiene Amigos ha de mostrarse Amigo

I think you need to pass a more general object,an object WUC_CreDes.WebForm1 and WUC_CreDes.WebForm2 are derived from like Page,

public static bool Hay_PostBack(System.Web.UI.Page page,....){}

_____________
Mehdi.
software student.

I'm coding:

public static bool Hay_PostBack(System.Web.UI.Page parent1, string w1,
string w1cx,
string w1ID,
string w2,
string w2cx,
string w2ID)
{
string fofoi = parent1.GetType().ToString();
if(fofoi == "ASP.WebForm1_aspx")
{

WUC_CreDes.WebForm1 frm = (WUC_CreDes.WebForm1) parent1;
}
else
{
if(fofoi == "ASP.WebForm2_aspx")
{
WUC_CreDes.WebForm2 frm = (WUC_CreDes.WebForm2) parent1;
}
}
But frm is not being recogniz by system
In what am I wrong???


El Hombre que tiene Amigos ha de mostrarse Amigo

you declared frm in {} so it's just recognized within {},
_____________
Mehdi.
software student.

Thanks you Mehdi:
But still I've an error.
My code is now:

public static bool Hay_PostBack(System.Web.UI.Page parent1, string w1,
                string w1cx,
                string w1ID,
                string w2,
                string w2cx,
                string w2ID)
        {
                WUC_CreDes.WebForm1 frm1;
                WUC_CreDes.WebForm2 frm2;

                string fofoi = parent1.GetType().ToString();
                if(fofoi == "ASP.WebForm1_aspx")
                {
                    frm1 = (WUC_CreDes.WebForm1) parent1;

    frm1.parent1.Example.Controls.Clear();
}
}

When I compile, in line: frm1.parent1.Example.Controls.Clear();
is sending me this error:
'WUC_CreDes.WebForm1' haven't a deffinition to 'parent1' Why?
I'll thank your help
A.L.

El Hombre que tiene Amigos ha de mostrarse Amigo

because : 'WUC_CreDes.WebForm1' haven't a deffinition to 'parent1'

try,
frm1.Example.Controls.Clear();

_____________
Mehdi.
software student.

I'm sorry Mehdi, but still doing as you told me error persist.
Example is a place holder contening both in WebForm1 and in WebForm2.

I’ll thank your help.


El Hombre que tiene Amigos ha de mostrarse Amigo

Finally I found the solution:

To call function:

bool que = WUC_CreDes.Class1.Hay_PostBack(this, w1,w1cx, w1ID, w2, w2cx, w2ID);

The function:

public static bool Hay_PostBack(System.Web.UI.Page parent1, string w1,
                string w1cx,
                string w1ID,
                string w2,
                string w2cx,
                string w2ID)
        {
                WUC_CreDes.WebForm1 frm1;
                WUC_CreDes.WebForm2 frm2;

                string cual = "";
                cual = HttpContext.Current.Session["par1"].ToString();

                string fofoi = parent1.GetType().ToString();
                if(fofoi == "ASP.WebForm1_aspx")
                {
                    frm1 = (WUC_CreDes.WebForm1) parent1;


                    frm1.Example.Controls.Clear();


                                if(cual == w1)
                                {
                                    Control control = frm1.Page.LoadControl(w1cx);
                                    control.ID = w1ID;
                                    frm1.Example.Controls.Add(control);
                                }
                                else
                                {
                                    Control control = frm1.Page.LoadControl(w2cx);
                                    control.ID = w2ID;
                                    frm1.Example.Controls.Add(control);
                                }
                }
                else
                {
                    if(fofoi == "ASP.WebForm2_aspx")
                    {
                        frm2 = (WUC_CreDes.WebForm2) parent1;
                        frm2.Example.Controls.Clear();

                                    if(cual == w1)
                                    {
                                        Control control = frm2.Page.LoadControl(w1cx);
                                        control.ID = w1ID;
                                        frm2.Example.Controls.Add(control);
                                    }
                                    else
                                    {
                                        Control control = frm2.Page.LoadControl(w2cx);
                                        control.ID = w2ID;
                                        frm2.Example.Controls.Add(control);
                                    }
                    }
                }
            return false;
        }

Greetings.

A.L.


El Hombre que tiene Amigos ha de mostrarse Amigo