Hello,

Could please someone explain me why these two senteces don't cause a execution error

char letters[]="ABCDE";
letters[0]='X';

whereas these two sentences do cause and error in execution time?

char* letters2="ABCDE";
*(letters2)='X';

I understand that what I am doing in the first block is to create an array called letters with the values A,B,C,D,E and /n.

In the second block, from what I have understood from my manual, you are creating a pointer to char, and at the same time, you are initialiazing the value for that memory position with the letter A, and the following positions with B,C,D,E, and /n.

But what I don't understand is why I cannot access the position pointed by letters2, and change the first letter.

Thank you in advance for your help.

After assigning a string value to a variable of type char*, you use index to access it's elements. Just like array of chars.
Although letter2 itself is a pointer to the first element of the string, you can't change it's value using asterisk(*) operator.
you can test this simply by printing memory addresses in a console application..

Hope that helped...

yes, an example here c++ pointer address when using a pointer to point to a memory address in a simplified example without even using an array.