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Old December 7th, 2006, 05:08 AM
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Default Invalid conversion from 'char*' to 'char'

I'm trying to write a calculator that takes command line arguments. So if someone wants to add 2 and 2 they would type:
Code:
$./prog a 2 2
argv[1] would be the desired operation, while argv[2] and argv[3] would be the numbers. This is my code so far:

Code:
#include <iostream>
#include <cmath>
#include <cstdlib>

using namespace std;

int addition(int a, int b){
int c;
c=a+b;
return (c);
}


int main(int argc, char    *argv[]){
char x(argv[1]);
int a, b;
a = atoi(argv[2]);
b = atoi(argv[3]);


switch (x) {
    case "a":
        addition(a,b);
        break;
    default:
        cerr << "Undefined operation.";
}

return 0;

}
Every time I try to compile this GCC gives me these errors:
Code:
 In function 'int main(int, char**)':
 error: invalid conversion from 'char*' to 'char'
 error: case label does not reduce to an integer constant
make: *** [calcpp] Error 1
How can I use the value of argv[1] in a switch statement? My best attempts at deciphering the error messages point to that. Thanks in advance.


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  #2 (permalink)  
Old December 7th, 2006, 08:51 AM
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Default

Hey there. Your only problem is that you are declaring it right just forgetting to follow up.

Basically you declare char *argv in your main function

which was right but when you declared char x = argv[1] you forgot to say it was a pointer

so all you do is add an asterisk in front of argv[1] and you have it as a char =P

now as far as the switch statement . . .

it will accept characters as long as you put them in as characters

so this step depends on your compiler but the best practice is to put characters in single quotes

mainly becouse this is the most common standard and most compilers dont like chars in double quotes

so if you say 'a' instead of "a" it works

I did it myself heres the code :

#include <iostream>
#include <cmath>
#include <cstdlib>

using namespace std;

int addition(int a, int b) {
     int c;
     c=a+b;
     return (c);
}


int main(int argc, char *argv[]) {
     char x = *argv[1];
     int a, b;
     a = atoi(argv[2]);
     b = atoi(argv[3]);


     switch(x) {
          case 'a':
               cout << addition(a,b);
               break;
          default:
               cerr << "Undefined operation.";
     }

     return 0;
}


~ Geo

 ~ You are unique, just like everyone else
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Old December 7th, 2006, 01:25 PM
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Default

Thanks a lot Geo! That did the trick.

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Old December 8th, 2006, 07:56 AM
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No problemo! That's what I'm here for =P

Keep up the good work!

~ Geo

 ~ You are unique, just like everyone else
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