Validation for special character

nazneen · September 2nd, 2003, 01:01 AM

Hi,

I need to validate a string for numeric and special character such that the string should contain minimum of 1 numeric digit and 1 special character.
I tried checking it with all special characters one by one but i feel its not a very good idea, a better thing would be to check each character first for an alphabet(A-z or a-z) else for a number else it is a special chacter.
But I dont know how to use this.
I checked out on the sites for a function containsonly but I am not very sure of how to use it.
Please tell me how do i check for an alphabet,number.

Thanking in Advance
Naz

egolileopablo · September 2nd, 2003, 03:18 AM

try this and you can set the foreground too.
use
getContentPane().setBackground(color.red)

pushfriends · February 8th, 2005, 03:56 AM

Hello Friends,

Here is the code to check for an alphabet,number etc.
It is tested and working code. Just use it.
Happy Programming.

Pushp.
-------

<HTML>
<HEAD>
<head>
<meta name="GENERATOR" content="Microsoft FrontPage 5.0">
<meta name="ProgId" content="FrontPage.Editor.Document">
<meta name="Author" content="Pushpendra: <[email protected]>">
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
<title>Pushpendra:<[email protected]>: Java Script Strong Password Validtions</title>

<script language="javascript">
function isStrongPassword()
{

   var control = document.form1.password;
   var myString= control.value;

   var Stringlen = myString.length;
   var ValidateDigits = /[^0-9]/g;
   var ValidateSpChar = /[a-zA-Z0-9]/g;
   var ValidateChar = /[^a-zA-Z]/g;

   var digitString = myString.replace(ValidateDigits , "");
   var specialString = myString.replace(ValidateSpChar, "");
   var charString = myString.replace(ValidateChar, "");

   if(Stringlen < 8)
   {
   alert("Passwords must be at least 8 characters");
   control.value="";
   control.focus();
   return false;
   }
   if(specialString < 1)
   {
   alert("Passwords must include at least 1 special (#,@,&,$ etc) characters");
   control.value="";
   control.focus();
   return false;
   }
   if(digitString < 1)
   {
   alert("Passwords must include at least 1 numeric characters");
   control.value="";
   control.focus();
   return false;
   }
   return;
}
</script>

</HEAD>
<BODY>

<P><h2>Registration</h2>
<form id=form1 name=form1>
<table>
<tr><td>Login:</td>
<td><INPUT id=login name=login size="20"></td>
</tr>
<tr><td>Password:</td>
<td><INPUT id=password name=password size="20"></td>
</tr>
</table>
<P><INPUT id=register type=button value=Register name=register onclick='javascript:isStrongPassword()'></P>
</form>
</BODY>
</HTML>

"Deleted code has fewer bugs."

sonicDace · February 8th, 2005, 05:42 PM

If you want to apply Push's example to java, look into java.util.regex.pattern class:

http://java.sun.com/j2se/1.5.0/docs/...x/Pattern.html

Hope this helps ;)

peterna · February 9th, 2006, 11:13 AM

This certainly keeps bad passwords out.

However, the form you attached the JavaScript to does absolutely nothing useful. Please help!

And after adding "action=index.html" to the form, it still does nothing. Cleaning out the non-contributing table and font coding still gets me no action. I think I will stick to a simple validation script that applies only one regular expression such as /[a-zA-Z0-9]/g; and then allow the login to actually log someone in.

pushfriends · February 13th, 2006, 03:13 PM

Hi Peter,

I had created a demo form for the post. You can copy Java script function and paste it any where. Fire the function at any amy event.

In case of any problem do write to me at [email protected]

Pushpendra

"Deleted code has fewer bugs."