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Old December 11th, 2003, 12:40 AM
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Default finding the string before a special character

Suppose i have an xml file.
i have to write an xsl file so that it should allow characters from
a-z and A-Z and numbers and '_' and '/'.
if the string is having any other character then it should display the string before the special character.
if the string is not having any other special characters then it should display normally.

my xml file is:

<?xml version="1.0"?>

in this case the output should be :
pease give a solution to this.

Old December 11th, 2003, 06:20 AM
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Send a message via Yahoo to armmarti

Here is the stylesheet:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:variable name="allowed" select="'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890_/'"/>

    <xsl:template match="emp">
        <xsl:for-each select="name">
            <xsl:call-template name="cut-bad-string">
                <xsl:with-param name="str" select="."/>

    <xsl:template name="cut-bad-string">
        <xsl:param name="str"/>
        <xsl:param name="idx" select="1"/>

            <xsl:when test="string-length($str) &lt; $idx">
                <xsl:value-of select="$str"/>
            <xsl:when test="string-length(normalize-space(translate(substring($str, $idx, 1), $allowed, ''))) = 0">
                <xsl:call-template name="cut-bad-string">
                    <xsl:with-param name="str" select="$str"/>
                    <xsl:with-param name="idx" select="$idx + 1"/>
                <xsl:value-of select="substring($str, 1, $idx - 1)"/>
Old December 16th, 2003, 07:57 AM
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Hello Armmarti,
it is working fine.


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