Hi all,

I have a situation where there is a one to many relation ship between two tables and I need to select only one of the records in the second table depending on the existance of particular value in a particular field.

For example
TableA: ID
TableB: ID, TableAID, Field1, Field2

Table A
1
2
3

Table B
1,1,value1,value3
2,1,value2,value3
3,2,value2,value3

desired results
1,1,value1,value3
3,2,value2,value3
null,3,null,null

[I edited the results from my original post as they where incorrect, please ignor results in email.]

The 2,1,value2,value3 record is ommited because there is a value1 available.
The TableAID = 3 still has to be returned as a right outer join

If there is a record for the TableAID that has value1 in the Field1 column then I need to select that record, as in TableAID=1
However if there is not a value1 in the table for Field1 I need to select the value2 record, as in TableAID=2

But still only returning one record per TableAID.

This is far less complex than the query i have to work with but I think it illustates the problem.

Any Assistance will be grately appreciated.





======================================
"They say, best men are molded out of faults,
And, for the most, become much more the better
For being a little bad."
--Shakespeare
======================================

__________________
======================================
"They say, best men are molded out of faults,
And, for the most, become much more the better
For being a little bad."
--Shakespeare
======================================

I made some assumptions due to other possible requirements that you didn't supply or where in error.
Are the field1 values really just two possible values?
Resultset??
id tableaid field1 field2
1 1 value1 value3
2 2 value2 value3
3 NULL NULL NULL

HTH
<code>
DECLARE @tablea TABLE (id int)
DECLARE @tableb TABLE (id int, tableaid int, field1 varchar(10), field2 varchar(10))
INSERT INTO @tablea SELECT 1
INSERT INTO @tablea SELECT 2
INSERT INTO @tablea SELECT 3
INSERT INTO @tableb SELECT 1,1,'value1','value3'
INSERT INTO @tableb SELECT 2,1,'value2','value3'
INSERT INTO @tableb SELECT 3,2,'value2','value3'

SELECT
      a.id
    , CASE WHEN b.field1 IS NOT NULL THEN b.tableaid ELSE c.tableaid END
    , ISNULL(b.field1, c.field1)
    , CASE WHEN b.field1 IS NOT NULL THEN b.field2 ELSE c.field2 END
FROM @tablea a
    LEFT JOIN (SELECT * FROM @tableb WHERE field1 = 'value1') b ON a.id = b.tableaid
    LEFT JOIN (SELECT * FROM @tableb WHERE field1 = 'value2') c ON a.id = c.tableaid
</code>

Adam Gossage
Lake Wylie, SC, USA

Hi Adam,
Thanks very much for your time.
Yes, your version of the resultset is correct, thankyou and my appologies for not being clear.
There can be more than two values for field1 but only two of the values are of concern for this query.

Your solutions looks great, thanks very much for that.
Now I have the task of putting this into my real situation.
Which I believe I can do thanks to your assistance.

======================================
"They say, best men are molded out of faults,
And, for the most, become much more the better
For being a little bad."
--Shakespeare
======================================