Hi,
i am using XPath to parse a file
I am using this imports

import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;

And this is how i parse a XPath Expression

XPath xpath = XPathFactory.newInstance().newXPath();
String expr = "Vendor/text()";
String brand = xpath.evaluate(expr,rdf);
(Where rdf is a node)

But i realize that using the expr stated above, or
String expr = "vendor/text()"; (notice that vendor starts with a lower case v)
is not the same thing

Is there anyway i can tell the XPath evaluator to disregard the case of the expression?

Thank you

No. XML is case-sensitive.

Well, if you really have to, you can do

*[lower-case(name()) = 'vendor']/text()

in XPath 2.0.

But there's something badly wrong with your XML document design if you have this requirement.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Thanks
The XML Document Design i am using is not mine, it's a standard for Mobile Phones, know as UAPROF, but i've noticed that some (very few) don't follow the correct Case, so i'm pretty much tied up here, because each vendor does what they want
But thanks for your anwser

If you have to handle dirty XML (XML that doesn't conform to its specification) then the best way to do it is to write a separate transformation that cleans it up before doing any further processing. Don't let the dirty XML get near your applications, and don't try to make your applications handle dirty XML as well as clean XML.



Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference