As 'id' is a special function in Xquery I believe. Is there a way to reference this node in Xquery. Ie:

<assets>
  <asset>
    <id>1</id>
  </asset>
  <asset>
    <id>2</id>
  </asset>
</assets>

$allAssets := $currentDoc/assets/asset/id

The id() function in XQuery selects nodes that, in the language of the XDM data model, have the "is-id" property. In practice a node can be given this property in three ways:

* by declaring an attribute of type ID in a DTD

* by declaring an element or attribute of type xs:ID in the schema

* by naming an attribute xml:id.

The fact that your elements are named <id> does not give them this property, or make them special in any other way. So you select them and process them exactly as you would an element called foo.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Hmm interesting. I was using a default namespace created by someone else and when i was counting the id elements it was returning 0 (incorrect). I've managed to fix this now by using the namespaces explictly for each path and now it works, whether this is a flaw or just my lack of understanding I dont know but I saw this with Ipedo's Xquery implementation.

Thanks
Ash