Hi there,

Another breadcrumb problem. I tried to figure it out with one of the previous post, but I got stuck :(

Here's my XML file:

<Menus>
<Menu_id>1</Menu_id>
<Main_Menu_Nr>1</Main_Menu_Nr>
<Main_Menu_Name>Principles and Tricks</Main_Menu_Name>
<Parent_Menu_nr>0</Parent_Menu_nr>
<Page_id>215</Page_id>
</Menus>

<Menus>
<Menu_id>2</Menu_id>
<Main_Menu_Nr>2</Main_Menu_Nr>
<Main_Menu_Name>Changing Chords</Main_Menu_Name>
<Parent_Menu_nr>1</Parent_Menu_nr>
<Page_id>217</Page_id>
</Menus>

<Menus>
<Menu_id>3</Menu_id>
<Main_Menu_Nr>3</Main_Menu_Nr>
<Main_Menu_Name>Inversions</Main_Menu_Name>
<Parent_Menu_nr>1</Parent_Menu_nr>
<Page_id>628/Page_id>
</Menus>

<Menus>
<Menu_id>4</Menu_id>
<Main_Menu_Nr>4</Main_Menu_Nr>
<Main_Menu_Name>The Bass</Main_Menu_Name>
<Parent_Menu_nr>1</Parent_Menu_nr>
<Page_id>136</Page_id>
</Menus>

<Menus>
<Menu_id>5</Menu_id>
<Main_Menu_Nr>5</Main_Menu_Nr>
<Main_Menu_Name>The Melody</Main_Menu_Name>
<Parent_Menu_nr>1</Parent_Menu_nr>
<Page_id>560</Page_id>
</Menus>

<Menus>
<Menu_id>6</Menu_id>
<Main_Menu_Nr>6</Main_Menu_Nr>
<Main_Menu_Name>Inversion</Main_Menu_Name>
<Parent_Menu_nr>3</Parent_Menu_nr>
<Page_id>345</Page_id>
</Menus>

<Menus>
<Menu_id>7</Menu_id>
<Main_Menu_Nr>7</Main_Menu_Nr>
<Main_Menu_Name>Moving Up and Down</Main_Menu_Name>
<Parent_Menu_nr>3</Parent_Menu_nr>
<Page_id>359</Page_id>
</Menus>

etc.

Where <Parent_Menu_nr> is the parent, pointing to <Menu_id>

The names are to show up in a breadcrumb trail with a <a href= ..> link to the page <Page_id>.html added.

I am but a musician and no XSLT programmer and I reaaally tried.
Rgghh.

If anyone could point me in the right direction, I'd be very grateful.

Cheers,

Matt Brandt
email: [email protected]

Hi again,

This is an addition to he previous post.
I came up with this, but didn't get any output
This is an edit of a previously posted xslt file.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
     version="1.0"
     xmlns:redirect="http://xml.apache.org/xalan/redirect"
     extension-element-prefixes="redirect">

    <xsl:param name="menu-id" select="1"/>

    <xsl:template match="Menus">
        <xsl:call-template name="output-bread-crumb">
            <xsl:with-param name="current" select="/Parent_menu_nr"/>
        </xsl:call-template>
    </xsl:template>

    <xsl:template name="output-bread-crumb">
        <xsl:param name="current"/>
        <xsl:choose>
            <xsl:when test="@current != 0">
                <xsl:call-template name="output-bread-crumb">
                    <xsl:with-param name="current" select="$current/@Parent_menu_nr"/>
                </xsl:call-template>
                &gt; <xsl:value-of select="$current/@Main_Menu_Name"/>
            </xsl:when>
            <xsl:otherwise>
                <xsl:value-of select="$current/@Main_Menu_Name"/>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>
</xsl:stylesheet>

What am I doing wrong ?
Thanks in advance

Matt
email:[email protected]

P.s. by Breadcrumb I mean one of those long lines with parts of menus and submenus : Mainmenu -> Menu 1.1 -> Menu 1.1.2 etc.

And so I solved it myself :

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
     version="1.0">
<!--
    A breadcrumb routine, where
    Main_Menu_Nr = number of a menu
    Main_Menu_Name = title of menu, to be put in breadcrumb
    Parent_Menu_nr = number of Parent, to be compared with Main_Menu_Nr
                   = 0 when there is no parent

    This routine calculates the breadcrumbs for ALL the Menu items.
    Output is a list of all the breadcrums
-->

    <xsl:variable name="newline">
    <xsl:text>
    </xsl:text>
    </xsl:variable>
    <xsl:variable name="breadc" select = "*" >
    </xsl:variable>

    <xsl:template match="dataroot">
        <xsl:for-each select ="Menus">
            <xsl:value-of select = "$newline"/>
            <xsl:value-of select = "Main_Menu_Nr"/>
            <xsl:call-template name="bc">
                        <xsl:with-param name="breadc" select="Main_Menu_Name" />
                        <xsl:with-param name="parentnr" select ="Parent_Menu_nr"/>
            </xsl:call-template>
        </xsl:for-each>
    </xsl:template>

    <xsl:template name="bc">
          <xsl:param name="breadc" />
          <xsl:param name="parentnr"/>
          <xsl:choose>
                 <xsl:when test="$parentnr &gt; '0'">
                       <xsl:for-each select ="//Menus">
                         <xsl:if test ="Main_Menu_Nr = $parentnr" >
                               <xsl:call-template name="bc">
                             <xsl:with-param name="breadc" select= "concat (Main_Menu_Name,'---',$breadc)"/>
                            <xsl:with-param name="parentnr" select = "Parent_Menu_nr"/>
                            </xsl:call-template>
                    </xsl:if>
                </xsl:for-each>
          </xsl:when>
          <xsl:when test="$parentnr = '0'">
                   <xsl:value-of select= "concat(' ',$breadc)" />
                 </xsl:when>
             </xsl:choose>
    </xsl:template>
</xsl:stylesheet>

Cheers,

Matt 'xslmatty' Brandt