I have the following XML

<?xml version="1.0" encoding="windows-1252"?>
<root>
  <xform id = "Nwb Incident Management" xmlns="http://www.w3.org/2000/xforms">
    <module>
      <value1>test</value1>
      <value2>test</value2>
    </module>
  </xform>
</root>

I want to select the root node
    then the module, so I have to pass the xform node

but I can not select module because the xform node could not be found. when I remove the 'xmlns="http://www.w3.org/2000/xforms"' out of the xml and it works fine.

This is my code

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.1" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:output method="xml" version="1.0" indent="yes" />

                <xsl:template match = "/" >
                        <xsl:apply-templates select = "root"/>
                </xsl:template>

                <xsl:template match = "root" >
        <order_list>
                <xsl:apply-templates select="xform"/>
        </order_list>
                </xsl:template>

                <xsl:template match="xform" >
                        <xsl:apply-templates select = "module"/>
                </xsl:template>

http://www.dpawson.co.uk/xsl/sect2/N...tml#d6408e1012



--

Joe (Microsoft MVP - XML)

To select a node that's in a namespace, you need to use a prefix. Any prefix will do so long as it's bound to the right namespace. E.g.

<xsl:apply-templates select="x:xform" xmlns:x="http://www.w3.org/2000/xforms"/>

You would normally declare this namespace on the xsl:stylesheet element because you will probably be using it all over the place. Note that the children of the xform element are also in this namespace.



Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Thank you all!!!

This is what I was looking for.
It is working perfect, after 2 weeks of trying.