I want to transform 'source.xml' to 'target.xml'. can any body help me in writing the Style sheet.

source.xml:-
============

<TD5>
  <separator>*</separator>
  <value>123</value>
  <separator>*</separator>
  <value>45</value>
  <separator>*</separator>
  <separator>*</separator>
  <separator>*</separator>
  <value>ALL WEIGHTS PEPS-RIDGF</value>
</TD5>

target.xml:-
============
<TD5>
  <value>123</value>
  <value>45</value>
  <value/>
  <value/>
  <value>ALL WEIGHTS PEPS-RIDGF</value>
</TD5>

Logic:- The source.xml has <td5> document element and two child elements, namely <separator> and <value>. Each <separator> element is "optionally" followed by a <value> element.

The logic to be implemented is, if the <separator> element is followed by a <value> element then that <value> element should go into target.xml and If <separator> element is NOT FOLLOWED by a <value> element then for every two continuous <separator> elements one new blank <value> element (which is <value/>) should go into the target.xml.

In the given source.xml there are three continuous <separator> elements and hence in the target.xml they are replaced by 2 <value/> elements.

Yo!

Kinda easy... I don't think you tried to hard...

Here's your solution mate:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:template match="TD5">
  <xsl:copy>
   <xsl:apply-templates select="separator"/>
  </xsl:copy>
 </xsl:template>
 <xsl:template match="separator">
  <xsl:element name="value">
   <xsl:if test="following-sibling::node()[1][name()='value']">
    <xsl:value-of select="following-sibling::node()[1]"/>
   </xsl:if>
  </xsl:element>
 </xsl:template>
</xsl:stylesheet>

Next time, try to solve your problem a little before getting free code. This forum is here to help people, not to provide cheap labor.

Hasta la vista!

Rushman

Dijkstra's law on Programming and Inertia:

If you don't know what your program is supposed to do, don't try to write it.

Thak you rushman. To be honest with you I tried for over a week (I just strated using XSLT), may be I'm dumb? Thanks a lot.

Hi Rushman,

Once again thanks for your help. The free program that you gave did not work. I'm using "xalan" on Linux OS. Never the less it served the purpose of giving me the idea.

When I'm using your xslt sheet the output that i got is as follows ..

  <?xml version="1.0" encoding="UTF-8" ?>
 <TD5>
  <value />
  <value />
  <value />
  <value />
  <value />
 </TD5>

The xslt-sheet that I came up with is as follows. Of course , there is no big difference between your xslt and mine. I'm using * and you are using node(). What I could not understand is why doesn't your xslt which uses node() give the same output as mine that uses *? Does this have anything to do with XALAN or if everything is working as expected and your code is not complete ;)

<?xml version="1.0" ?>
 <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="TD5">
  <TD5>
    <xsl:apply-templates select="separator" />
  </TD5>
  </xsl:template>

   <xsl:template match="separator">
   <value>
    <xsl:if test="following-sibling::*[1][name()='value']">
   <xsl:value-of select="following-sibling::*[1]" />
  </xsl:if>
  </value>
 </xsl:template>
</xsl:stylesheet>