2 XML Docs > 1 XSLT Stylesheet

kwilliams · September 9th, 2005, 09:26 AM

I've posted this question before with no response, so I decided to simplify my explanation in hopes of making it easier to understand what I'm asking about:

I have 2 XML docs:
1) xmldoc1.xml - This file contains a central list of external links for our entire website. This is how it's set up:
<xmldoc1>
    <site id="site1">
        <url>http://www.site1.com/</url>
    </site>
    <site id="site2">
        <url>http://www.site2.com/</url>
    </site>
</xmldoc1>

2) xmldoc2.xml - This file contains a node named "link" that matches one of the "id" attributes from xmldoc1.xml. This is how it's set up:
<xmldoc2>
    <item>
        <title>SITE 1</title>
        <address>123 4th St.</address>
        <phone>(123) 456-7890</phone>
        <link>site1</link>
    </item>
    <item>
        <title>SITE 2</title>
        <address>987 6th St.</address>
        <phone>(987) 654-3210</phone>
        <link>site2</link>
    </item>
</xmldoc2>

And this is what I'd like the output to look like:

SITE 1
Address: 123 4th St.
Phone: (123) 456-7890
Website: http://www.site1.com/

SITE 2
Address: 987 6th St.
Phone: (987) 654-3210
Website: http://www.site2.com/

I know that I need an XSLT stylesheet that ties the 2 source XML docs together using the "id" attribute from xmldoc1.xml, and the "link" node from xmldoc2.xml, but I'm not sure how to accomplish this. I've been beating my head against a wall concerning what I thought would be a simple task, so I'm now hoping that some knowledgable folks can show me the light so-to-speak.

So if anyone can give me some insight in how to accomplish this task, it would be greatly appreciated!!! Thanks so much for your time.

KWilliams

joefawcett · September 9th, 2005, 01:08 PM

This should show you how to get started, run it against xmldoc2.xml.

Code:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="html" />
  <xsl:param name="linkDocPath" select="'xmldoc1.xml'" />
  <xsl:variable name="linkDoc" select="document($linkDocPath)" />
  <xsl:template match="/">
    <html>
      <head>
        <title>Sites</title>
      </head>
      <body>
        <xsl:apply-templates select="*/item" />
      </body>
    </html>
  </xsl:template>

  <xsl:template match="item">
    <xsl:variable name="url" select="$linkDoc/*/site[@id = current()/link]/url" />
    <h3><xsl:value-of select="title" /></h3>
    <div>Address: <xsl:value-of select="address" /></div>
    <div>Phone: <xsl:value-of select="phone" /></div>
    <div>Web site: <a href="{$url}"><xsl:value-of select="$url" /></a></div>
  </xsl:template>

</xsl:stylesheet>

--

Joe (Microsoft MVP - XML)

kwilliams · September 9th, 2005, 01:49 PM

Hi Joe,

Thanks for a quick, thorough, and correct answer to my question. It worked GREAT! You are a great asset to this forum:)

P.S.
I used this:
<xsl:variable name="linkDoc" select="document('xmldoc1.xml')" />

...instead of this:
<xsl:param name="linkDocPath" select="'xmldoc1.xml'" />
<xsl:variable name="linkDoc" select="document($linkDocPath)" />

...and it still worked great. Thanks.

KWilliams

joefawcett · September 12th, 2005, 11:22 AM

Quote:

quote:You are a great asset to this forum:)

Thanks

The reason I did it in two stages was that it's easier then to change the value of the XML file brought in via the document() function by externally setting the param named "linkDocPath".

--

Joe (Microsoft MVP - XML)