HOW TO: Display specified # of nodes

kwilliams · October 5th, 2005, 10:10 AM

How can I set up a <xsl:for-each...> method that uses an <xsl:if...> statement to display specified number of nodesets?

I'm basically wanting to display a set of data from an XML doc in a 3-column display using CSS positioning using <div> tags.

This is how I'd like it to be set up, but I'm not sure how to accomplish the "COUNT" of the nodesets:

Code:

<xsl:for-each select="root/element">
    <xsl:if test="COUNT <= '10'>
        <div id="columnA">
            <xsl:value-of select="childnode" />
        </div>
    </xsl:if>
    <xsl:if test="COUNT >= '11' and COUNT <= '20'>
        <div id="columnB">
            <xsl:value-of select="childnode" />
        </div>
    </xsl:if>
    <xsl:if test="COUNT >= '21' and COUNT <= '30'>
        <div id="columnC">
            <xsl:value-of select="childnode" />
        </div>
    </xsl:if>
</xsl:for-each>

Any & all help is appreciated. Thanks.

KWilliams

mhkay · October 5th, 2005, 11:00 AM

Just use the position() function whereever you've written COUNT. And of course you need to escape "<" as "<".

But it would be better to do three for-each loops:

<xsl:for-each select="(root/element)[position() <= 10]">
...

etc.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

kwilliams · October 5th, 2005, 11:04 AM

Great. Thanks for the information, the quick response, and the suggestion concerning the 3 for-each loops instead. I'll give it a try right now.

KWilliams