Hi,

I have a problem trying to return nodes in sequential order from the following example. The 'for each' statement that I'm using only returns the 1st node (5 times in this example). I've divided the code into 2 parts (the XML & the XSL) and this example only has the 1st node used in the output file:

[u]XML</u>
<ShippingInstructions ShippingType="Delivery">
<ShippingDate DateTimeType="Earliest Delivery">20060214 07:00</ShippingDate>
<ShippingDate DateTimeType="Dispatch Date">20060214</ShippingDate>
<ShippingDate DateTimeType="Earliest Available">20060214 07:00</ShippingDate>
<ShippingDate DateTimeType="Latest Available">20060214 07:00</ShippingDate>
<ShippingDate DateTimeType="Latest Delivery">20060214 17:00</ShippingDate>
<Description>D/O 6263/1+6198/1+6902/1 38484</Description>
</ShippingInstructions>

[u]XSL</u>
<xsl:when test="@ShippingType='Delivery'">
....
<xsl:call-template name="ha"/>
</xsl:when>

<xsl:template name="ha">
<xsl:attribute name="ShippingType"><xsl:text>Delivery</xsl:text></xsl:attribute>
<xsl:for-each select="ShippingDate">
<xsl:element name="ShippingDate">
<xsl:variable name="EarlDel" select="../ShippingDate"/>
<xsl:attribute name="DateTimeType">Earliest Delivery</xsl:attribute>
<xsl:value-of select="$EarlDel"/>
</xsl:element>
</xsl:for-each>
</xsl:template>

[u]Question 1</u>
I'm sure it's the select statement is my problem but please can anyone help?

[u]Question 2</u>
Also, each time I loop through the 'for each' statement I need to populate the output with the next node. How do I do this?

Please understand, I'm fairly new to this.

Thanks,


Neal

A Northern Soul

__________________
Neal

A Northern Soul

I'm a bit puzzled by your problem because your code seems to be written very carefully to select the first Shipping Date. Let's walk through it:

<xsl:for-each select="ShippingDate">
-- for each ShippingDate in the input

<xsl:element name="ShippingDate">
-- create a ShippingDate in the output

<xsl:variable name="EarlDel" select="../ShippingDate"/>
-- create a variable whose value is the set of all ShippingDate elements owned by the parent of this ShippingDate

<xsl:attribute name="DateTimeType">Earliest Delivery</xsl:attribute>
-- create an attribute whose name is "DateTimeType" and whose value is the string "Earliest Delivery"

<xsl:value-of select="$EarlDel"/>
-- output the string-value of the first node in the set $EarlDel, that is, the first child of the parent ShippingInstructions.

If you want to output the current node, just do <xsl:value-of select="."/> in the usual way, but then all the stuff about labelling it as the "earliest delivery" is nonsense.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Yes, I know it's perhaps my unclear explanation in the aforementioned code. Sorry!

<xsl:variable name="EarlDel" select="../ShippingDate"/>
-- create a variable whose value is the set of all ShippingDate elements owned by the parent of this ShippingDate

I do not want to return all shippingDate elements 'in one go' as you correctly stated.

So, how do I populate each ShippingDate element (DateTimeType) into 'EarlDel' individually (one at a time)? I need to evaluate each ShippingDate element.


Neal

A Northern Soul

You do it the way I said, using <xsl:value-of select="."/>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference