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Old February 14th, 2006, 09:27 AM
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Default Sorting with XSL

Hello, I hope someone can help me.
I have the folloging XML data:

<shop_articles>
  <article id="1" order="50" show="yes">
    <article_groups>
      <article_group>
        <name>Group1</name>
    <value>value of group1</value>
      </article_group>
      <article_group>
    <name>Quality</name>
    <value>good</value>
      </article_group>
      ...
    </article_groups>

    <article_price>400</article_price>
  </article>

  <article id...
  </article>
</shop_articles>

I am using a <xsl:for-each > instruction to loop through all articles. When I want to sort the articles by the price it works fine with <xsl:sort select="*[name()='article_price']" /> after the <xsl:for-each>.

But I don´t know what to do to sort the articles for example by the <value> of <article_group>´s with the <name>Quality</name>.

Any one have an idea?
Thanks you very much in advance.

Greetings, Wolfgang
 
Old February 14th, 2006, 10:19 AM
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Default

For your first sort you can simplify to:
Code:
<xsl:sort data-type="number" select="article_price" />
For the sort based on article_group/name equal to "quality":
Code:
<xsl:sort data-type="text" select="article_groups/article_group[name = 'Quality']/value" />
This assumes that the value element has text data, if it's a number then change data-type attribute to "number".

--

Joe (Microsoft MVP - XML)
 
Old February 14th, 2006, 10:25 AM
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Default

>it works fine with <xsl:sort select="*[name()='article_price']" />

It would work even finer with <xsl:sort select="article_price"/>

>But I don´t know what to do to sort the articles for example by the <value> of <article_group>´s with the <name>Quality</name>.

<xsl:sort select="article_groups/article_group[name='Quality']/value"/>



Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference





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