Turning XML into HTML

[email protected] · June 7th, 2006, 03:45 PM

I have an XML document as follows:

Code:

<?xml version="1.0" ?>
<?xml-stylesheet type="text/xsl" href="ZoneType_TEXT.xsl"?>
<ZoneContent>
  <paragraph style="Heading2" link="http://www.sqlservercentral.com" linktitle="Sql Server Central" window="1">This is a test</paragraph>
  <paragraph>This is another</paragraph>
  <paragraph>This is another</paragraph>
</ZoneContent>

What I want to do is to itterate through the paragraph tags and convert them into HTML so that Heading 2 wraps everything up in HTML H2 tags.

If There is a link then there will be an <h2><a href="http://www.sqlservercentral.com" title="Sql Server Central" target="1">This is a test paragraph</a></h2>

My XSLT looks as follows

Code:

<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:template match="/">
        <xsl:for-each select="ZoneContent/paragraph">
        <xsl:choose>
            <xsl:when test="@style='Heading1'">
                <xsl:element name="h1">
                    <xsl:appy-templates select="."/>
                </xsl:element>
            </xsl:when>
            <xsl:when test="@style='Heading2'">
                <xsl:element name="h2">
                    <xsl:appy-templates select="."/>
                </xsl:element>
            </xsl:when>
            <xsl:when test="@style='Heading3'">
                <xsl:element name="h3">
                    <xsl:appy-templates select="."/>
                </xsl:element>
            </xsl:when>
            <xsl:when test="@style='Heading4'">
                <xsl:element name="h4">
                    <xsl:appy-templates select="."/>
                </xsl:element>
            </xsl:when>
            <xsl:otherwise>
                <xsl:element name="p">
                    <xsl:appy-templates select="."/>
                </xsl:element>
            </xsl:otherwise>
        </xsl:choose>
        </xsl:for-each>
    </xsl:template>

    <xsl:template match=".">
        <xsl:choose>
            <xsl:when test="@link">
            <xsl:element name="a">
                  <xsl:attribute name="href" >
                 <xsl:value-of select="@link" />
               </xsl:attribute>
               <xsl:attribute name="title">
                <xsl:value-of select="@linktitle" />
               </xsl:attribute>
               <xsl:attribute name="target">
                 <xsl:value-of select="@window" />
               </xsl:attribute>
            <xsl:value-of select="current()"/>
            </xsl:element>
            </xsl:when>
        <xsl:otherwise>
            <xsl:value-of select="current()"/>
        </xsl:otherwise>
        </xsl:choose>

    </xsl:template>
</xsl:stylesheet>

but it gives errors saying that I can't post at this time.

I am really banging my head against this and should be grateful for any help that can be given.

isme · June 8th, 2006, 04:36 AM

Does this do what you want:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:template match="/">
        <xsl:for-each select="ZoneContent/paragraph">
        <xsl:choose>
            <xsl:when test="@style='Heading1'">
                <xsl:element name="h1">
                </xsl:element>
            </xsl:when>
            <xsl:when test="@style='Heading2'">
                <xsl:element name="h2">
                </xsl:element>
            </xsl:when>
            <xsl:when test="@style='Heading3'">
                <xsl:element name="h3">
                </xsl:element>
            </xsl:when>
            <xsl:when test="@style='Heading4'">
                <xsl:element name="h4">
                </xsl:element>
            </xsl:when>
            <xsl:otherwise>
                <xsl:element name="p">
                </xsl:element>
            </xsl:otherwise>
        </xsl:choose>
        </xsl:for-each>
        <xsl:apply-templates/>
    </xsl:template>

    <xsl:template match="paragraph">
        <xsl:choose>
            <xsl:when test="@link">
            <xsl:element name="a">
                  <xsl:attribute name="href" >
                 <xsl:value-of select="@link" />
               </xsl:attribute>
               <xsl:attribute name="title">
                <xsl:value-of select="@linktitle" />
               </xsl:attribute>
               <xsl:attribute name="target">
                 <xsl:value-of select="@window" />
               </xsl:attribute>
            <xsl:value-of select="current()"/>
            </xsl:element>
            </xsl:when>
        <xsl:otherwise>
            <xsl:value-of select="current()"/>
        </xsl:otherwise>
        </xsl:choose>

    </xsl:template>
</xsl:stylesheet>

mhkay · June 8th, 2006, 05:20 PM

match="." is not a valid match pattern. To match all elements, use match="*".

>but it gives errors saying that I can't post at this time.

Please post the actual error message even if you don't understand it. The chances are that someone else does.

Try to solve this problem without using for-each and xsl:choose. It's much better to write a template rule for each kind of element, which does apply-templates to process the children of that element.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference