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Old September 4th, 2006, 08:46 AM
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Default translate element name to element name

Hi,

How to translate:

<aName att1="1" att2="2" att3="3">

to

<differentName att1="1" att2="2" att3="3">

?

Currently I use something like this:

<xsl:template match="aName">
    <xsl:element name="differentName">
        <xsl:attribute name="att1">...</xsl:attribute>
        <xsl:attribute name="att2">...</xsl:attribute>
        <xsl:attribute name="att3">...</xsl:attribute>
        <xsl:copy-of select='./*'/>
    ...
    </xsl:element>
...
</xsl:template>

which I don't think is ugly and get locked with those explicit attribute definitions.

Any opinion?

 
Old September 4th, 2006, 08:49 AM
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typo

>which I don't think is ugly and get locked with those explicit attribute definitions.

which I do think is ugly and get locked with those explicit attribute definitions.

 
Old September 4th, 2006, 08:55 AM
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<xsl:template match="aName">
    <xsl:element name="differentName">
        <xsl:copy-of select='./@*'/>
        <xsl:copy-of select='./*'/>
    ...
    </xsl:element>
...
</xsl:template>

This will define new name but retain the attributes and children..
Other way more straight forward than this, anyone?


 
Old September 4th, 2006, 09:04 AM
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You can copy all the attributes using <xsl:copy-of select="@*"/>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference




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