The code line below works correctly using an XSLT v1.0 engine but gives the following error when using an v2.0 engine...

XPTY0004: Cannot compare xs:integer to xs:string

<xsl:if test="position() = '35'"> <xsl:call-template name="Seq"></xsl:call-template></xsl:if>

Has anyone else experienced this ??
Thx

Ben

XSLT 2.0 has stronger typechecking. If you want to compare an integer to a string, you either have to convert the string to an integer or vice versa. In this case, write "position() = 35".

The reason for the change is to prevent some of the inconistencies taht arise in the 1.0 spec, for example in 1.0 if position() is 4, then

position() >= '004' returns true, but

position() = '004' returns false.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference