Render HTML tags

jacksprophet · December 28th, 2006, 02:38 AM

I have this XML:

Code:

<text>
    This is some text.<br /><br /><quote>This is a quote.</quote>
    <br /><br />Some more text.<br /><br />One more line.
</text>

The XSL:

Code:

<xsl:template match="/">
   <html>
   <body>
       <xsl:apply-templates/>
   </body></html>
</xsl:template>

<xsl:template match="quote">
   <blockquote>
       <xsl:copy-of select="."/>
   </blockquote>
</xsl:template>

The problem:
The linebreaks don't render. Is there a way around this?

mhkay · December 28th, 2006, 07:03 PM

You need to add another template rule:

<xsl:template match="br">
<br/>
</xsl:template>

The default rule copies the content of an element but not the tags.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference