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Old December 28th, 2006, 02:38 AM
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Default Render HTML tags

I have this XML:

Code:
<text>
    This is some text.<br /><br /><quote>This is a quote.</quote>
    <br /><br />Some more text.<br /><br />One more line.
</text>
The XSL:

Code:
<xsl:template match="/">
   <html>
   <body>
       <xsl:apply-templates/>
   </body></html>
</xsl:template>

<xsl:template match="quote">
   <blockquote>
       <xsl:copy-of select="."/>
   </blockquote>
</xsl:template>
The problem:
The linebreaks don't render. Is there a way around this?
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Old December 28th, 2006, 07:03 PM
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Default

You need to add another template rule:

<xsl:template match="br">
  <br/>
</xsl:template>

The default rule copies the content of an element but not the tags.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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