Generic templates and only one node()

Clyne · #1 (**permalink**) January 3rd, 2007, 07:14 PM

Hi folks,
is it possible to program generic templates, which iterate through only one node-set? So I have one node-set, I get it with document(), and I want to rename elements on it. With the code below I get exactly the same number of trees, how /rule/rules//pattern matched. I know that node()* is an array, but I don't have any idea for a better strategy, because variables aren't changeable.

Code:

<xsl:template match="/">        
  <xsl:variable name="tree" as="node()*">
    <xsl:apply-templates select="//pattern"/>
  </xsl:variable>
<!--in $tree are x-trees and in every tree the rename 
of the process before is loosed. If I could change this fact, I 
could output the last tree from this array and it would be ok.-->
  <xsl:for-each select="$tree">
   <xsl:copy-of select="."/>
  </xsl:for-each>
</xsl:template>


<xsl:template match="/rule/rules//pattern" as="node()">
  <xsl:param name="document" select="document(another File)"/>
  <xsl:apply-templates select="$document" mode="document_">
  <xsl:with-param .. few parameter/>
  </xsl:apply-templates>
</xsl:template>

<xsl:template match="@*|node()" as="node()" mode="document_">
  <xsl:param ..get here with-param/>
  <xsl:choose>
    <xsl:when test"..">
      <xsl:element name="..">
        <xsl:apply-templates select="@*|node()" mode="document_"/>
      </xsl:element>
    </xsl:when>
    <xsl:otherwise>
      <xsl:copy>
        <xsl:apply-templates select="@*|node()" mode="document_"/>
      </xsl:copy>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>
</xsl:stylesheet>

Thanks for help.

Clyne

mhkay · #2 (**permalink**) January 3rd, 2007, 07:25 PM

Without knowing what your input is and what output you want to produce, I can't possibly make any suggestions on how you should write your code.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Clyne · #3 (**permalink**) January 3rd, 2007, 07:58 PM

..thanks for help

Code:

<rule>
  <rules>
    <pattern>
      <xpath attribute1="p1" attribute2="p1_"/>
    </pattern>
    <pattern>
      <xpath attribute1="p2" attribute2="p2_"/>
    </pattern>
  </rules>
</rule>


<test>
  <p1/>
  <p2/>
  <p3/>
</test>

<xsl:for-each select="$tree">
   <xsl:copy-of select="."/>
  </xsl:for-each>

<test>
  <p1_/>
  <p2/>
  <p3/>
</test>
<test>
  <p1/>
  <p2_/>
  <p3/>
</test>


<test>
  <p1_/>
  <p2_/>
  <p3/>
</test>

Clyne

mhkay · #4 (**permalink**) January 4th, 2007, 08:21 PM

Try something like this (you seem to be using XSLT 2.0):

<xsl:variable name="rulesdoc" select="/"/>
<xsl:variable name="testdoc" select="document('test.xml')"/>

<xsl:key name="mapping" match="xpath" use="@attribute1"/>

<xsl:template match="/">
  <xsl:apply-templates select="$testdoc/*"/>
</xsl:template>

<xsl:template match="test">
  <xsl:copy>
    <xsl:for-each select="*">
       <xsl:element name="{key('mapping', name(), $rulesdoc)/@attribute2}"/>
    </xsl:for-each>
  </xsl:copy>
</xsl:template>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Clyne · #5 (**permalink**) January 5th, 2007, 12:47 AM

With my sincere thanks, it works perfectly.

Clyne

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