I have the following XML code:

<p:tNumbers>
            <p:Number p:MType="Telephone" p:Usage="Business Line">
                <p:NumberElement p:ElementType="CountryCode">1</p:NumberElement>
             </p:Number>
</p:Numbers>

    <cb:Body>
            <cb:Students>
                <cb:residency label="west" unit="Pct">75</cb:residency>
                <cb:residency label="east" unit="Pct">25</cb:residency>
            </cb:Students>
    </cb:Body>
I get the actual node name - "tNumber" and "students" with "name()"

and I get actual children names by using "."
How can I use XSL to get the actual types...example - "Thelephone" or "CountryCode" or "west", "east" in the output.

Thanks.

You can access the value of an attribute node using an expression such as

<xsl:value-of select="@p:ElementType"/>

Make sure that (a) you are positioned on the right element as context node, and (b) that the namespace prefix p is declared in the stylesheet.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Is there an easier function that will access the value of every single attribute node in a tree?

You can use //@* to access every attribute in the document
e.g.
    <xsl:for-each select="//@*">
        <xsl:value-of select="name()" /> = <xsl:value-of select="." /> <br />
    </xsl:for-each>

The expression //@* selects all the attribute nodes in a document.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference