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Old February 27th, 2007, 07:13 AM
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Default xsl:if

can i put xsl:if like this??
<xsl:if test="string(local-name()) = 'frame'|string(local-name())='repeatingFrame'|string(local-name())='field'|string(local-name())='text'">

mens i want to check for multiple condition...wat to do?

 
Old February 27th, 2007, 07:50 AM
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The "or" operator in XPath is written "or". The "|" operator forms the union of two node-sets. In some contexts "|" has the same effect as "or", for example

test="b|c"

tests whether the union of child::b and child::c contains any elements, which is exactly the same as writing test="b or c". But this equivalence only applies when the operands are node-sets.

Note that you don't need to apply the string() function to the result of local-name() because the result of local-name() is already a string.

Do you actually want to ignore the namespace URI of the elements? Usually this is questionable practice. I would normally recommend writing

test="self::frame | self::repeatingFrame | self::field | self::text"

which differs from your code in that it requires the element to be in no-namespace.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference





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