Hi,

 As i am newbie to this XSLT. Please help me, I have written code for converting XML to required XML structure.

My part of input file:

<ol type="1">
<li>First</li>
<li>Second</li>
</ol>

my XSL:

<xsl:template match="//ol">
<xsl:call-template name="list"/>
</xsl:template>


<xsl:template name="list">
        <list>
            <xsl:attribute name="listType"><xsl:text>ordered</xsl:text></xsl:attribute>
            <xsl:attribute name="styleCode">
            <xsl:choose>
            <xsl:when test="@type='1'">
            <xsl:text>Arabic</xsl:text>
            </xsl:when>
            <xsl:when test="@type='a'">
            <xsl:text>LittleAlpha</xsl:text>
            </xsl:when>
            <xsl:when test="@type='i'">
            <xsl:text>LittleRoman</xsl:text>
            </xsl:when>
            <xsl:when test="@type='I'">
            <xsl:text>BigRoman</xsl:text>
            </xsl:when>
            <xsl:when test="@type='A'">
            <xsl:text>BigAlpha</xsl:text>
            </xsl:when>
            <xsl:otherwise>
            <xsl:text>Arabic</xsl:text>
            </xsl:otherwise>
            </xsl:choose>
            </xsl:attribute>
            <xsl:apply-templates select="li"/>
        </list>
    </xsl:template>

But it is working fine for the above scenario. But its not working for list within list(nested list) like the following.


<ol type="1">
<li>First</li>
<li>Second</li>
<ol type="a">
<li>Inner1</li>
<li>Inner2</li>
<li>Inner3</li>
</ol>
<li>Third</li>
</ol></div>

The first level is only getting covnerted. My case will have n level nested like the above.

Thanks in advacne.

For most XSLT transformations, and especially when handling an input structure that's recursive, you should use the standard recursive-descent design pattern where you write a template rule for matching each element, and it uses apply-templates to process its children.

<xsl:template match="//ol">
<xsl:call-template name="list"/>
</xsl:template>

The "//" at the start of the match pattern achieves nothing. Use match="ol". (The only difference is the priority of the rules if there are conflicts).

In your example the call-template achieves nothing, you could move the body of the called template inline.

<xsl:apply-templates select="li"/>

This says "process the li children". But your example also has "ol" children, and you aren't processing these. That's why they aren't being processed. Use <xsl:apply-templates/> to process all the children.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Mr Mkhay,

Thank you very much. It is working fine. Now i could make it what is the use of <xsl:applytemplates/>.

> what is the use of <xsl:apply-templates/>

Apply-templates is central to the processing model of XSLT. Read about it in your favourite XSLT textbook, and come back with questions if there are specific points you don't understand.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference