xslt -> xhtml validation

rahulsk1947 · May 16th, 2007, 11:49 AM

hi,i have written a stylesheet to transform a xml to xhtml.And i need to validate the xhtml produced.
I tried validating my code,but i get error.

Code:

<!DOCTYPE html PUBLIC 
    "-//W3C//DTD XHTML 1.0 Transitional//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">    


<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"  
xmlns="http://www.w3.org/1999/xhtml" >    


<xsl:output method="xml" indent="yes"
     doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"
    doctype-public="-//W3C//DTD XHTML 1.0 Transitional//EN" />

    <xsl:template match="/">
        <html>
            <body>
            </body>
        </html>
    </xsl:template>

</xsl:stylesheet>

i tried to validate it at http://validator.w3.org/ by copying and pastign the code.it doesn't seem to work. there seems to be some major mistake i am making.hope someone can rectify and corect my errors.would apreciate it.thanx alot

mhkay · May 16th, 2007, 12:10 PM

If your XHTML is invalid then we need to see the XHTML and the error messages, how you generated the XHTML is irrelevant.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

rahulsk1947 · May 16th, 2007, 10:44 PM

I was writing a xslt to transform a xml to xhtml.
the main outline of the code is:

<?xml version="1.0" encoding="utf-8" ?>
<!DOCTYPE html PUBLIC
    "-//W3C//DTD XHTML 1.0 Transitional//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.w3.org/1999/xhtml" >

    <xsl:template match="/">
        <html>
            <body>
            </body>
        </html>
    </xsl:template>

</xsl:stylesheet>

i tried to validate it at http://validator.w3.org/, but it fails.

the errors i get are:
Line 8 column 24: there is no attribute "version"
Line 8 column 40: there is no attribute "xmlns:xsl"
Line 9 column 6: there is no attribute "xmlns".
Line 9 column 37: element "xsl:stylesheet" undefined.
Line 14 column 24: there is no attribute "match".
Line 14 column 27: element "xsl:template" undefined.
Line 16 column 17: document type does not allow element "body" here.
Line 18 column 14: end tag for "html" which is not finished.
Line 21 column 17: no document element.

I had also refered to the site http://www.objectsbydesign.com/projects/xslt/xhtml.html whose tutorial is based on a reference to XSLT Programmer's Reference page. 250-261

I really need some one to guide and correct my errors.I need to get it to be a valid xhtml.thanx alot

mhkay · May 17th, 2007, 02:54 AM

The XHTML validator is designed to validate an XHTML file: that is, the output file produced when you run your stylesheet. It is not designed to validate the stylesheet itself, which is what you appear to be doing.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference