array to tree

Baldo · November 6th, 2003, 05:39 AM

Code:

 <xsl:variable name="root" select="/"/>

Code:

    <xsl:template match="/">
        <catalogo>
            <xsl:for-each select="fn:distinct-values(//autore)">
                   <autore>
                       <nome><xsl:copy-of select="."/></nome>
                    <xsl:variable name="nome" select="."/>
                       <xsl:copy-of select="$root/biblioteca/libro[autore=$nome]/titolo"/>
                   </autore>
              </xsl:for-each>
          </catalogo>
    </xsl:template>

wanna eliminate the
<xsl:for-each select="fn:distinct-values(//autore)">
is there a function to transform the array "fn:distinct-values(//autore)" to a tree, without using the for-each instrunction?

tnx :)

xslt learner :)

armmarti · November 7th, 2003, 01:42 PM

In XPath 2.0 sequence becomes the main construct. I couldn't find any function which "transforms" a sequence to a tree (look at http://www.w3.org/TR/xpath-functions/#d1e5620). And how can you imagine the arguments of that generic, hypothetical function which will "transform" any sequence to a tree(and how the structure of that destination tree will be given by arguments)? Definitely, you have to walk over the sequence and output the nodes you want, there is no other way.

Regards,
Armen

Baldo · November 7th, 2003, 01:49 PM

tnx :)

xslt learner :)