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Old September 22nd, 2007, 12:39 AM
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Default importing XML file in to xslt

<?xml version="1.0" encoding="UTF-8"?>
<Descriptions>
<Bugdetails category="MALICIOUS_CODE">
<Bug abbrev="MS">
<ShortDescription>Creates an empty jar file entry (AM_CREATES_EMPTY_JAR_FILE_ENTRY)</ShortDescription>
<LongDescription>
The code calls putNextEntry(), immediately followed by a call to closeEntry(). This results in an empty JarFile entry. The contents of the entry should be written to the JarFile between the calls to putNextEntry() and closeEntry().

</LongDescription>
</Bug>
</Bugdetails>

</Descriptions>


Above is my sample ref.xml doc.
there can be multiple <Bugdetails> elements and multiple <bug>with in each <Bugdetails>.

Now I want to use this ref.xml into my xslt for the bug Descriptions on the basis of abbrev code.
So i want ot import this xml doc into my xslt file and get the bug details in my xslt(test.xsl).


My seneario is

My test.xsl will be applies to another xml doc and fetch bug category and abbrev .then on the basis on those 2 values , will fetch corresponding bug details form this ref.xml file.


any idea is appreciated

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Old September 22nd, 2007, 02:25 AM
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Default

To load the XML file, use

<xsl:variable name="bugs" select="document('ref.xml')"/>

assuming the file is in the same directory as your stylesheet.

To select the bugs with a given category and abbreviation, use

select="$bugs/Descriptions/Bugdetails[@category=$category and Bug/@abbrev=$abbrev]"

If the file is very large you can make this search more efficient by using keys (though if you use Saxon-SA it will be optimized for you automatically).

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Old September 22nd, 2007, 11:15 PM
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Thanks Michael..
it really works..


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