copy xml-to-xml

kay · November 18th, 2003, 10:09 PM

I have a 2-step transformation requirement. first step goes just fine, transforming xml-to-xml using xslt. For step 2, I need to use the transformed xml of step 1 as input to create the final document. The final document needs to be fully tagged xml.

Using Mr. Kay's book as a guide, I coded an xslt with an xsl:copy-of. The output contained all the data, but no tags! So I decided to try xsl:copy using the example code on pg 194 of 2nd edition, as follows:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="@* | node()" mode="copy">
    <xsl:copy>
        <xsl:apply-templates select="@*" mode="copy"/>
        <xsl:apply-templates mode="copy"/>
    </xsl:copy>
</xsl:template>
</xsl:stylesheet>

Again, the result has no tags!

[u]What do I need to do to get the tags copied from xml to xml?</u>

regards, kay

joefawcett · November 19th, 2003, 04:36 AM

I'm not sure what the point of your transformation is but two things, when you say no tags how are you viewing the result? In a browser if it doesn't recognise it as an xml document you'll just see the text between elements. Secondly the identity transform normally used is below, it copies everything and you can override for certain nodes by adding extra templates matching those nodes.

Code:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="node()|@*">

    <xsl:copy>

      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>
  <!--
    Templates to match nodes that need changing go here
  -->
</xsl:stylesheet>

Joe (MVP - xml)

kay · November 19th, 2003, 06:49 PM

Quote:

quote:Originally posted by joefawcett
I'm not sure what the point of your transformation is but two things, when you say no tags how are you viewing the result? In a browser if it doesn't recognise it as an xml document you'll just see the text between elements. Secondly the identity transform normally used is below, it copies everything and you can override for certain nodes by adding extra templates matching those nodes.

Code:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  
  <xsl:template match="node()|@*">

    <xsl:copy>
      
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>
  <!--
    Templates to match nodes that need changing go here
  -->
</xsl:stylesheet>

Joe (MVP - xml)

regards, kay

kay · November 19th, 2003, 06:51 PM

Thanks for your response. I was able to achieve what I needed by reversing my steps and using the document() function. I still need to figure out how to make document() respond to a variable that java code will manipulate. Thanks again! :)

Quote:

quote:Originally posted by joefawcett
I'm not sure what the point of your transformation is but two things, when you say no tags how are you viewing the result? In a browser if it doesn't recognise it as an xml document you'll just see the text between elements. Secondly the identity transform normally used is below, it copies everything and you can override for certain nodes by adding extra templates matching those nodes.

Code:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  
  <xsl:template match="node()|@*">

    <xsl:copy>
      
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>
  <!--
    Templates to match nodes that need changing go here
  -->
</xsl:stylesheet>

Joe (MVP - xml)

regards, kay

kay · November 19th, 2003, 06:55 PM

One more thing, I think the biggest reason I was getting no tags (as viewed by xmlspy) was because of a namespace issue. The document I was trying to transform was of a different namespace, so all my matches were not matching. I added a namespace qualifier to all the node names of the input document, and suddenly things got much better. The parser was invoking the builtin templates, which dumped all the data, but none of the tags...

Quote:

quote:Originally posted by joefawcett
I'm not sure what the point of your transformation is but two things, when you say no tags how are you viewing the result? In a browser if it doesn't recognise it as an xml document you'll just see the text between elements. Secondly the identity transform normally used is below, it copies everything and you can override for certain nodes by adding extra templates matching those nodes.

Code:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  
  <xsl:template match="node()|@*">

    <xsl:copy>
      
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>
  <!--
    Templates to match nodes that need changing go here
  -->
</xsl:stylesheet>

Joe (MVP - xml)

regards, kay