converting dates: day of week

stolte · November 27th, 2007, 05:22 PM

Is there an easy way using XSLT 2.0 to find out the day of the week (Monday, Tuesday, etc) from the date format 2008-01-01T00:00:00-06:00?

I know about using exslt extensions, but need a solution that would be supported by Saxon.

mhkay · November 27th, 2007, 05:52 PM

Use format-date() and one of the options is to get the day of the week, which will be in a standard representation if you use the ISO calendar.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

stolte · November 28th, 2007, 11:24 AM

If I want to convert 2008-11-28T00:00:00-06:00 to Wednesday 11/28 am I correct to assume the following function is correct:

assuming $d is 2008-11-28T00:00:00-06:00

format-date($d, "[FNn] [M01]/[D01]")