Hi,

my xml:
<?xml version='1.0'?>
<AAA >
         <BBB ooo = "111" ppp = "222" >
             <CCC>c1 </CCC>
             <CCC>c2 </CCC><break></break>
         </BBB>
         <BBB ooo = "555" ppp = "666" >
             <DDD>d1 </DDD><break></break>
             <DDD>d2 </DDD>
             <DDD>d3 </DDD>
             <DDD>d4 </DDD><break></break>
             <DDD>d5 </DDD>
         </BBB>
     </AAA>

my xsl:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="1.0">
        <xsl:template match="/">
         <QQQ>
                 <xsl:copy-of select="//BBB" />
         </QQQ>
        </xsl:template>
</xsl:stylesheet>

my html o/p:

<?xml version="1.0" encoding="UTF-8"?><QQQ><BBB ooo="111" ppp="222">
             <CCC>c1 </CCC>
             <CCC>c2 </CCC><break/>
         </BBB><BBB ooo="555" ppp="666">
             <DDD>d1 </DDD><break/>
             <DDD>d2 </DDD>
             <DDD>d3 </DDD>
             <DDD>d4 </DDD><break/>
             <DDD>d5 </DDD>
         </BBB></QQQ>


i want to replace <break></break> with <br></br>
how can i do this.

i tried using this template

<xsl:template name="SubstringReplace">
<xsl:param name="stringIn" />
<xsl:param name="substringIn" />
<xsl:param name="substringOut" />
<xsl:choose>
    <xsl:when test="contains($stringIn,$substringIn)">
    <xsl:value-of
        select="concat(substring-before($stringIn,$substringIn),$substringOut)" />
    <xsl:call-template name="SubstringReplace">
    <xsl:with-param name="stringIn"
    select="substring-after($stringIn,$substringIn)" />
<xsl:with-param name="substringIn"
select="$substringIn" />
<xsl:with-param name="substringOut"
                        select="$substringOut" />
                </xsl:call-template>
            </xsl:when>
            <xsl:otherwise>
                <xsl:value-of select="$stringIn" />
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>


and

                            <xsl:copy-of>
                                        <xsl:variable name="myString" select="./node()" />
                                            <xsl:variable name="myNewString">
                                            <xsl:call-template name="SubstringReplace">
                                                <xsl:with-param name="stringIn" select="$myString"/>
                                                <xsl:with-param name="substringIn" select="'break'"/>
                                                <xsl:with-param name="substringOut" select="'br'"/>
                                                </xsl:call-template>
                                                </xsl:variable>
                                            <xsl:value-of select="concat('input: ',$myString,'output: ',$myNewString)"/>
                                                    </xsl:copy-of>



i am not able to compile if i use the above xsl

what may be the problem and how can we declare variables for xsl:copy-of.


Raj

hi

i hav tried with this example also

xml:

<?xml version='1.0'?>
<winelist>

  <wine grape="Chardonnay">
    <winery>Benziger</winery>
    <product>Carneros</product>
    <year>1997</year>
    <desc>Well-textured flavors, good finish.</desc>
    <prices>
      <list>10.99</list>
      <discounted>9.50</discounted>
      <case>114.00</case>
    </prices>
  </wine>

  <wine grape="Cabernet">
    <winery>Duckpond</winery>
    <product>Merit Selection</product>
    <year>1996</year>
    <desc>Sturdy and generous flavors, long finish.</desc><finish></finish>
    <prices>
      <list>13.99</list>
      <discounted>11.99</discounted>
      <case>143.50</case>
    </prices>
  </wine>

</winelist>


xsl:

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="@*|*">
  <xsl:copy>
    <xsl:apply-templates select="./node()"/>
  </xsl:copy>
</xsl:template>
<xsl:template match="text()">
  <xsl:call-template name="globalReplace">
  <xsl:with-param name="outputString" select="."/>
  <xsl:with-param name="target" select="'finish'"/>
  <xsl:with-param name="replacement" select="'FINISH'"/>
  </xsl:call-template>
</xsl:template>


    <xsl:template name="globalReplace">
        <xsl:param name="outputString" />
        <xsl:param name="target" />
        <xsl:param name="replacement" />
        <xsl:choose>
            <xsl:when test="contains($outputString,$target)">
                <xsl:value-of select="concat(substring-before($outputString,$target),$replacement)" />
                <xsl:call-template name="globalReplace">
                    <xsl:with-param name="outputString" select="substring-after($outputString,$target)" />
                    <xsl:with-param name="target" select="$target" />
                    <xsl:with-param name="replacement" select="$replacement" />
                </xsl:call-template>
            </xsl:when>
            <xsl:otherwise>
                <xsl:value-of select="$outputString" />
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>
</xsl:stylesheet>


my html o/p:

<?xml version="1.0" encoding="UTF-8"?><winelist>

  <wine>
    <winery>Benziger</winery>
    <product>Carneros</product>
    <year>1997</year>
    <desc>Well-textured flavors, good FINISH.</desc>
    <prices>
      <list>10.99</list>
      <discounted>9.50</discounted>
      <case>114.00</case>
    </prices>
  </wine>

  <wine>
    <winery>Duckpond</winery>
    <product>Merit Selection</product>
    <year>1996</year>
    <desc>Sturdy and generous flavors, long FINISH.</desc><finish/>
    <prices>
      <list>13.99</list>
      <discounted>11.99</discounted>
      <case>143.50</case>
    </prices>
  </wine>

</winelist>


but the finish tag is not replaced with FINISH as in the text template we are using select="." ,how can we change the text inside the tag.


......Raj

I would use a more traditional identity template. Then add the replace function and the template to match text. Then add a new template to match the finish element: --

Joe (Microsoft MVP - XML)

got it but didnt understand

 <xsl:template match="finish">
    <FINISH>
      <xsl:apply-templates select="@*|node()"/>
    </FINISH>
  </xsl:template>


why we need to use <FINISH> tag ..

Well you wanted a 'FINISH' element rather than a 'finish' element. If you have more specific rules that state that all elements in a specified set should be should have their names altered to be UPPERCASE then that's possible too. You just said, however, that 'finish' needed to be 'FINISH'.

--

Joe (Microsoft MVP - XML)

yep how can we do that

Raj

>i want to replace <break></break> with <br></br>
how can i do this.

>i tried using this template

<xsl:template name="SubstringReplace">

Your template is designed to replace strings in the XML content, whereas your requirement is to rename nodes. To rename a node, do

<xsl:template match="break">
  <br>
    <xsl:apply-templates/>
  </br>
</xsl:template>

(The apply-templates call is not needed, of course, if the element is always empty.)

By the way, please don't delete threads from the forum. There are people getting email notifications of your posting, and if they find the email in their inbox and recognize the problem as one where they would like to know the answer, it's very irritating to find the whole thread has been deleted. It's also irritating to people like me who answer posts to have my work deleted - if we thought you were the only person who needs the information, we wouldn't bother answering at all.

Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer's Reference

oops i am sorry for it,but i have deleted the post where there was no reply.
Anyways sorry