Can anyone tell me if there is a way to find elements that contain child element with the same local-name() nested some number of levels deep?

For example, let's say I want to create a stylesheet template that matches on any element nested 5 levels deep where its 4 ancestors have the exact same local-name(). Here's an example of what I'd like to be able to detect:

<foo>
   <bar><bar><bar><bar><bar></bar></bar></bar></bar></bar>
</foo>

but not

<foo>
   <bar><bar><bar></bar></bar></bar>
</foo>

I can't seen to figure out how to write an XPath expression that matches an element whose parent's local-name() is the same as its local-name().

Any assistance greatly appreciated.

<xsl:template match="bar/bar/bar/bar/bar">

if you know the name. If you don't know the name,

match="*[name(..)=name(current()) and name(../..)=name(current()) and name(../../..)=name(current()) and so on]"

Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer's Reference

Hi Michael,
Thank you very much! I'm in the second scenario where I don't know the name of the element, I simply want to do some processing when I see any element of the same name nested 'N' levels deep.

I was originally trying to do something along the lines of:

match="*[local-name() = ancestor::local-name()]/*[local-name() = ancestor::local-name()]" (etc.) and was apparently confusing both the XSLT processor and myself. :-)

Thanks again!