extract nested list

JohnBampton · February 25th, 2009, 11:25 PM

I have the following XML:

<list level="1">

<item>1</item>

<list level="2">

<item>1</item>

<item>2</item>

<item>3</item>

</list>

<item>2</item>

</list>

I would like to extract the nested list and insert it between item 1 and 2 of the parent list:

<list level="1">

<item>1</item>

</list>
<list level="1">

<item>1</item>

<item>2</item>

<item>3</item>

</list>
<list level="1">

<item>2</item>

</list>

Any suggestions?

mrame · February 26th, 2009, 12:45 AM

Try this:

Code:

 
<xsl:template match="list[@level = 1]">
<list>
<xsl:apply-templates></xsl:apply-templates>
</list>
</xsl:template>

<xsl:template match="list[@level = 1]/item">
<list level="1">
<xsl:copy-of select="."></xsl:copy-of>
</list>
<xsl:apply-templates select="list"></xsl:apply-templates>
</xsl:template>

<xsl:template match="list[@level = 2]">
<xsl:copy-of select="."></xsl:copy-of>
</xsl:template>

mhkay · February 26th, 2009, 04:20 AM

It's not shown by your example, but I suspect you want all adjacent items within a list to remain grouped. That makes it a group-adjacent problem:

Code:

<xsl:template match="list">
  <xsl:for-each-group select="*" group-adjacent="node-name(.)">
    <xsl:choose>
      <xsl:when test="self::item">
        <list><xsl:apply-templates select="current-group()"/></list>
      <xsl:when>
      <xsl:otherwise>
        <xsl:apply-templates/>
      </xsl:otherwise>
  </xsl:for-each-group>
</xsl:template>

<xsl:template match="item">
  <xsl:copy-of select="."/>
</xsl:template>

I haven't handled the level numbers there, and I don't know if it does the right thing with an empty list - you didn't specify. But it's a starter.

JohnBampton · February 26th, 2009, 06:14 AM

Thank you guys