I am trying to determine the total number of minutes from the start of the day until the <date> value. For example, if the 00 hour of the current date was:

Case 1:
basedate: 2010-11-07T00:00:00.000-06:00

<date>2010-11-07T01:00:00.000-05:00</date> //should return 00 min
<date>2010-11-07T01:00:00.000-06:00</date> //should return 60 min


Case 2:
basedate: 2010-11-07T00:00:00.000-05:00

<date>2010-11-07T01:00:00.000-05:00</date> //should return 60 min
<date>2010-11-07T01:00:00.000-06:00</date> //should return 120 min

My two questions are:

1. Is there a way to capture the current dateTime and reset the object to the 00 hour?

2. Once I have a base dateTime set at the 00 hour of the current day, I am able to take the difference of the base dateTime and the <date> value, but is there a way to calculate the total minutes of that difference? All I can think of is to use built in functions to get the hours, multiple by 60 and add the minutes. I just wasn't sure if there was a more efficient method.

Any help is greatly appreciated.

>I am trying to determine the total number of minutes from the start of the day until the <date> value

That looks like ($date2 - $date1) div xs:dayTimeDuration('PT1M')

I assume that makes your other questions irrelevant.

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

Thanks!

I do still have the open question, is it possible to capture the base dateTime by capturing the current-dateTime() and then change the time to 00:00:00 -5:00 using built-in XSLT functions? I looked at the spec, but couldn't find the magic bullet.

Does xs:date(current-dateTime()) give you what you want?

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

Wouldn't I then have to cast it back as a dateTime to get:

2009-18-12T00:00:00.000-06:00

and use that value for dateTime comparisons?

I will give it a try. Thanks!