What is the best approch to find root element ?

nisargmca · March 8th, 2010, 03:16 AM

Hi we have many xml file as input and we processed each one by one.Now for each xml we need to find root element and based on this we need to take decision how to process that xml accordingly.

Before this we are using DocumentBuilder's parse method to get Document object and then using getDocumentElement() of Document object to get root element .Now we find that when file is large then it throws out of memory error ?

So we need to find out that is it possible through xslt ? or we need to apply code that will parse whole xml and find root element ?

Can anybody pls help me ?

Thanks in Advance .

[email protected] · March 8th, 2010, 03:30 AM

You can find the root name like this:

Code:

 <xsl:template match="/">
     <xsl:value-of select="name(node())"/>
 </xsl:template>

Regards,
Anil Yadav

nisargmca · March 8th, 2010, 08:38 AM

Thanks a lot for reply.

I got the Root Node with the help of that xslt code.

Can i store this value with xslt and return to code which perform Transformation ?

mrame · March 8th, 2010, 09:23 AM

You can declare a global variable as below and use it any where inside the code:

Code:

<xsl:variable name="root" select="document(document-uri(.))/*[1]/name()"/>
 
<xsl:template match="/">
<xsl:value-of select="$root"/>
</xsl:template>

nisargmca · March 8th, 2010, 09:41 AM

Can i access this value outside the xslt ?

nisargmca · March 11th, 2010, 07:25 AM

Hi ,
I have solved my problem with StAX parser which stop the parsing when we get desire data.

Thanks a lot.