Multiple Inputs: collections

stolte · March 8th, 2010, 06:43 PM

I am using Saxon and XSLT 2.0. I have a document that lists all the files we want to process:

<files>
<file loc="path/filename.xml"/>
<file loc="path/filename.xml"/>
<file loc="path/filename.xml"/>
<file loc="path/filename.xml"/>
</files>

In the XSL, I need to process each file. Each file can have a different path. Is it possible to loop thru each <file> and process the nodes?

<xsl:for-each select="doc(file/@loc)">



</xsl:for-each>

Or is there a better approach?

stolte · March 8th, 2010, 06:46 PM

Or can you use something like <apply-templates select="doc(file/@loc)"/>?

mhkay · March 8th, 2010, 06:52 PM

A call on doc() takes a single URI and returns a single document.

To get multiple documents from multiple URIs, you could use select="document(loc/@href)". Another advantage of using document() here rather than doc() is that where the argument is a node, and the URI is relative, it is treated as being relative to the URI of that node (i.e. to the document containing the URIs), not relative to the stylesheet.

stolte · March 8th, 2010, 06:58 PM

To clarify, the following would work?

<xsl:template match="backbone">
<apply-templates select="document(file/@loc)"/>
</xsl:template>

<xsl:template match="document(file/@loc)">

</xsl:template>

Martin Honnen · March 9th, 2010, 09:09 AM

If the primary input file you showed in your original post has a 'files' root element then you could do e.g.

Code:

<xsl:template match="files">
  <xsl:apply-templates select="document(file/@doc)/node()"/>
</xsl:template>

and then you would need to write templates matching the nodes in those documents e.g. if the root elements in those documents are named 'foo' then you would use e.g.

Code:

<xsl:template match="foo">
  ...
</xsl:template>