Simplifying XML parents [XSLT]

FrozenGrapes · April 13th, 2010, 04:44 PM

I have an XML file that looks like this:

Code:

<A>
   <B.../>
   <C.../>
   <C.../>
   <C.../>
   <D.../>
   <D.../>
</A>

I am trying to come up with a way to format it like this using XSLT:

Code:

<A>
   <B.../>
   <C.../>
   <D.../>
</A>

I have tried a number of things like using for-each loops that compare the current name to the following-sibling and proceeding with that, however i run into problems when there are multiple, multiple instances. Ex. It works fine if there are multiple instances of ONLY C, but if there are multiples of C AND D, then my code will print out something like this:

Code:

<A>
   <B.../>
   <C...><D...></C></D>
</A>

This is because of the for-each loop going through ALL the elements even after its done what I want.

IMPORTANT:
For this I CANNOT specify C or D specifically. The paths have to be relative axes and generic enough to use for any multiples because these documents have as many as 30-50 multiples and uniquely specifying each one is not what I want.

If anyone can offer up ideas to help me with this it would be much appreciated.

Thanks.

mhkay · April 13th, 2010, 05:58 PM

If you're using XSLT 2.0 then it's just

<xsl:for-each-group select="*" group-adjacent="node-name()">
...
</xsl:for-each-group>

If you're stuck with XSLT 1.0, then use sibling recursion (google it)

FrozenGrapes · April 13th, 2010, 06:02 PM

Yeah, I am stick with 1.0. but, Ill give this a shot, looks promising. Thanks.