Printing the first 10 nodes that match criteria

toskers · October 29th, 2010, 08:28 PM

Hi all,

Below is an excerpt from my xml tree. I need to print out the first 10 <article> nodes. But I can't figure out how to count them. position() doesn't work since they appear under different parents. I'm trying to do something like:

for-each folder/article and counter < 10

print contents of article

Code:

<folder>
    <article>
    <article>
</folder>
<folder>
    <article>
</folder>
<folder>
    <article>
    <article>
    <article>
</folder>
<folder>
    <article>
    <article>
</folder>

Any help is appreciated.

mrame · October 30th, 2010, 02:04 AM

Try the below:

Code:

<xsl:variable name="article">
 <xsl:copy-of select="//article"/>
</xsl:variable>
 
<xsl:template match="root">
<xsl:copy-of select="$article/article[position() &lt; 11/>
</xsl:template>

there can be a better solution than this.