xsl link

RockBal · August 2nd, 2011, 10:43 AM

Hi,

I have xml element X-ref and AFF. i need link for X-Ref element, if i click x-ref element it will show the text for AFF element text. any one can help for the above link

<X-REF REFID="S021848851100709XAF001"></X-REF>
</AUT>
<AFF ID="S021848851100709XAF001">Sample text</AFF>

Regards,
Rockbal

samjudson · August 3rd, 2011, 03:22 AM

If you want the AFF element with the correct ID then you'd do something like this:

Code:

<xsl:template match="X-REF">
    <xsl:value-of select="//AFF[@Id=current()/@REFID" />
</xsl:template>

How you want to put this into something that responds to a user click depends on what you are using (e..g HTML? Javascript?) which you don't say.

RockBal · August 4th, 2011, 10:11 AM

the output format is HTML. I need to show X-REF attribute REFID values and then i click REFID i will show the corresponding AFF text. I used your code it will show error message (//AFF[@Id=current()/@REF ID: expected "]", found "<name>")Kindly Advise.

samjudson · August 4th, 2011, 10:32 AM

Well the error is pretty self explanatory - it says it is missing a ']', so try adding a ']'.

i.e. select="//AFF[@Id=current()/@REFID]"

If you show us the HTML you want to generate we can help you write the XSLT to output it.

RockBal · August 8th, 2011, 11:06 AM

Hi,

I need help for some one.

The below coding i tried but i'm not getting output.

Input file

<a REFID="#A3336C-1920">1. Heading 1</a>
<a REFID="#A3336C-1921">2. Heading 2</a>
1. This is Heading One
2. This is Heading Two

Output

<html>
<a id="ch03en01" /><a href="#en01ch03">1. Heading 1</a>
<a id="ch03en02" /><a href="#en02ch03">2. Heading 2</a>
<a id="en01ch03" /><a href="#ch03en01">This is Heading One</a>
<a id="en02ch03" /><a href="#ch03en02">This is Heading Two</a>
</html>
Please Kindly look at my input and output file for ur reference. Input is xml and output is html. give me the xsl coding for this occurrence.

Advance Thanks
Rockbal

samjudson · August 8th, 2011, 11:10 AM

I can't see any relationship between your input and your output. Where does "ch03en01" come from?

Oh, and for an <A> element to link to another element you should use the NAME attribute, not the ID attribute.

RockBal · August 8th, 2011, 11:17 AM

Sorry i pasted wrong attribute value. Kindly consider this as input and output.

Input file

<a REFID="ch03en01">1. Heading 1</a>
<a REFID="ch03en02">2. Heading 2</a>
1. This is Heading One
2. This is Heading Two

Output

<html>
<a id="ch03en01" /><a href="#en01ch03">1. Heading 1</a>
<a id="ch03en02" /><a href="#en02ch03">2. Heading 2</a>
<a id="en01ch03" /><a href="#ch03en01">This is Heading One</a>
<a id="en02ch03" /><a href="#ch03en02">This is Heading Two</a>
</html>

samjudson · August 8th, 2011, 12:20 PM

Well, you simply need a template to handle each <a> element, and each element. Then use of the substring() function should allow you to generate the required id.

Code:

<xsl:template match="a">
 <p>
    <a id="{@REFID}"/><a href="#{concat(substring(@REFID,4,3),substring(@REFID,1,3))}"><xsl:value-of select="."/></a>
</p>
</xsl:template>

<xsl:template match="b">
  <p>
      <a id="{concat(substring(@ID,4,3),substring(@ID,1,3))}"/><a href="#{@ID}"><xsl:value-of select="."/></a>
  </p>
</xsl:template>

Hopefully you can finish off the rest.