Finding the last occurance of character in the given string?

kvbhaskar7 · November 8th, 2011, 08:53 PM

Hi,

Is there any way to extract/find the last occurance of character in a string.

I have a string like "12,34,567" and i need to seperate 12,34 and assign a HTML class for last occurance of "," and append 567.

I have used the below code, but it is working only for first occurance.

<xsl:when test="../@char = ','">
<xsl:value-of select="substring-before(.,',')"/>
<span class="Align">,
</span>
<xsl:value-of select="substring-after(.,',')"/>
</xsl:when>

Any other suggestions?

mrame · November 9th, 2011, 02:27 AM

If you are sure that there will be only three values, then you can use the following:

Code:

<xsl:value-of select="substring-after(substring-after(@char,','),',')"/>

which will give the value 567.

kvbhaskar7 · November 9th, 2011, 02:35 AM

Thanks for your reply.

No, the value will change and number of "," occurances also changes. Is there any way to find out the last occurance?

mrame · November 9th, 2011, 03:39 AM

Would the follow help:

Code:

<xsl:value-of select="tokenize(@char,',')[last()]"/>

mhkay · November 9th, 2011, 06:28 AM

In XSLT 2.0, use the tokenize() function. In XSLT 1.0, you need to write a recursive template. Or rather you don't, because it's already been written - you can download the EXSLT str:tokenize template from www.exslt.org

kvbhaskar7 · November 14th, 2011, 04:17 PM

Found this recursive template which helped me to resolve the issue

Code:

<xsl:template name="substring-after-last">
  <xsl:param name="string" />
  <xsl:param name="delimiter" />
  <xsl:choose>
    <xsl:when test="contains($string, $delimiter)">
      <xsl:call-template name="substring-after-last">
        <xsl:with-param name="string"
          select="substring-after($string, $delimiter)" />
        <xsl:with-param name="delimiter" select="$delimiter" />
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise><xsl:value-of select="$string" /></xsl:otherwise>
  </xsl:choose>
</xsl:template>