Hi. I have a question how I can get something like sequencer or row number of elements which met criteria.

example: I have 5 elements with parameter start date like this
<phase type="Available" start="01.12.2012"/>

2 of them met criteria for example year is equal to actual year. I want to have some variable starts from 0, so in this case I will have 2 phases with ID 0 and 1.

Thanks in advance.

Depending on the overall processing structure (what happens to the nodes that don't meet the criteria?) the solution will either use position() or xsl:number. If you are only processing the nodes that meet the criteria, use

If you need to process the other nodes as well, try

with level="simple" if the nodes are all siblings, or level="any" otherwise.

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

thanks for quick replay :)

I need to set x position based on sequence number in group which met criteria. I cant use position() in this case


pseudo code:
if(year = acutal)
//1 element
<react x=0
//2 element
<rect x = 1
else if(year = year -1)
//1 element
<react x= 0
//2 element
<rect x = 1
//2 element
<rect x = 2
else if(year = year+1)
...

structure look like this:

<project type="Migration" name="Test">
<phase end="31.03.2018" type="Deprecated" start="31.03.2015"/>
<phase end="31.12.2013" type="Available" start="01.12.2012"/>
<phase end="30.11.2012" type="Migration" start="01.01.2012"/>
<phase end="30.11.2011" type="PoC" start="01.01.2011"/>
<phase end="31.10.2010" type="Evaluation" start="01.09.2010"/>
<phase end="31.10.2009" type="Migration" start="01.09.2009"/>
</project>

XSL look like
<xsl:template match="phase">
<xsl:choose>
<xsl:when test="$start=$end and date:year($start) = $year">
<polyline points="{$X}, {$Y} {$X+$project-font-size}, {$Y} {$X+$project-font-size * 1.5}, {$Y + $project-font-size * 0.5} {$X+$project-font-size}, {$Y + $project-font-size} {$X}, {$Y + $project-font-size} {$X}, {$Y}" class="phase {./@type}"/>
</xsl:when>
<xsl:when test="(date:year($start) &lt; ($year - 1 )) and (date:year($end) &lt; ($year - 1 ))">
<xsl:variable name="row_number">
//here I need for element 1 have 1, for element 2 value 2 etc - that each next element will be next to prevous
</xsl:variable>
<path class="phase {./@type}" d="m{row_number},{$Y + $project-font-size}.0,0l1.09375,-1.09375l-1.09375,-1.09375l-1.3125,0l1.03125,1.03125l-1.03125,1.15625z" />
</xsl:when>
<xsl:when test="(date:year($start) &gt; ($year + 1 )) and (date:year($end) &gt; ($year + 1 ))">
<path class="phase {./@type}" d="m162.5,{$Y + $project-font-size}.0,0l1.09375,-1.09375l-1.09375,-1.09375l-1.3125,0l1.03125,1.03125l-1.03125,1.15625z" />
</xsl:when>
<xsl:otherwise>
<xsl:variable name="W" select="$scale-another-year * ($dayslastyear + $daysnextyear) + $daysthisyear * $scale-this-year"/>
<rect x="{$X}" y="{$Y}" width="{$W}" height="{$project-font-size}" class="phase {./@type}"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

I've no idea what your pseudocode means. "if (year = year + 1)" makes no sense to me. Please show the output you require for this input.

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

sorry,
if (year = year + 1) means start date year = actual year +1

I need to have consecutive numbers of element met criteria starts from 0.

I tried also something like that:

but it doesnt work: