Replace throughout every element

JohnBampton · July 31st, 2012, 05:24 AM

Hi all,

Using XSLT 2.0/ Xpath 2.0 Saxon 9

I was wondering if there was an easy way to replace some text in every element in a XML file with XSL and then maybe store the whole XML in a variable and then do normal processing to it?

Anyone got a basic example?

mhkay · July 31st, 2012, 06:01 AM

Something like this, perhaps:

Code:

<xsl:template match="/">
  <xsl:variable name="post-replacement">
    <xsl:apply-templates select="." mode="replace"/>
  </xsl:variable>
  ... next phase of processing ...
</xsl:template>

<xsl:template match="*" mode="replace">
  <xsl:copy>
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates mode="replace"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="text()" mode="replace">
  <xsl:value-of select="replace(., 'abc', 'def')"/>
</xsl:template>