I have XSLT 2.0 (Saxon free edition 9.H.E)

my xml
<Group>
<Detail Custno="111" date="2012-11-01t06:00:00">
<Order Nr="1" name="xxx"/>
<Order Nr="2" name="yyy"/>
<Product id="1" type="a" lenght="10" height="15"/>
<Product id="1" type="a" lenght="105" height="15"/>
<Product id="1" type="b" lenght="12" height="15"/>
<Product id="1" type="a" lenght="13" height="15"/>
<Product id="1" type="b" lenght="10" height="13"/>
</Detail>
</Group>


Desired output

<Group>
<Time>2012-11-07T05:00:00</Time>
<Detail>
<CustNo>111</CustNo>
<OrderList>
<Order>
<Nr>1</Nr>
<name>xxx</name>
</Order>
<Order>
<Nr>2</Nr>
<name>yyy</name>
</Order>
</OrderList>
<ProductList>
<Product>
<id>1</id>
<type>a</type>
<Dimension>
<lenght>10</lenght>
<height>15</height>
</Dimension>
<Dimension>
<lenght>105</lenght>
<height>15</height>
</Dimension>
<Dimension>
<lenght>13</lenght>
<height>15</height>
</Dimension>
</Product>
<Product>
<id>1</id>
<type>b</type>
<Dimension>
<lenght>12</lenght>
<height>15</height>
</Dimension>
<Dimension>
<lenght>10</lenght>
<height>13</height>
</Dimension>
</Product>
</ProductList>
</Detail>
</Group>




I tried using xsl:for-each-group but i'm getting this error "xsl:for-each-group not yet implemented"

Please help

Well if you really use Saxon 9 then you shouldn't get that error message. That error message suggests you use an XSLT 1.0 processor like Microsoft's XslCompiledTransform in .NET 3.5 and 4.0 respectively Visual Studio. So make sure you use Saxon 9 and not the built-in XSLT processor in .NET or Visual Studio.

__________________
Martin Honnen
Microsoft MVP (XML, Data Platform Development) 2005/04 - 2013/03
My blog

Also, when reporting an error in your XSLT it can be helpful to show your XSLT, rather than us trying to guess what it looks like.

__________________
/- Sam Judson : Wrox Technical Editor -/

Think before you post: What have you tried?

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:fn="http://www.w3.org/2005/xpath-functions" xmlns:xdt="http://www.w3.org/2005/xpath-datatypes">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="no"/>

<xsl:key name="type" match="Product" use="@type" />

<xsl:template match="Group">
<xsl:message>
<Envelope>
<Time>
<xsl:value-of select="format-dateTime(current-dateTime(), '[Y0001]-[M01]-[D01]T[H01]:[m01]:[s01]')" />
</Time>
<Detail>
<CustNo>
<xsl:value-of select="//Group/Detail/@CustNo"/>
</CustNo>
<OrderList>
<xsl:for-each select="//Order">
<Order>
<Nr>
<xsl:value-of select="@Nr"/>
</Nr>
<name>
<xsl:value-of select="@name"/>
</name>
</Order>
</xsl:for-each>
</OrderList>
<ProductList>
<xsl:for-each-group select="Detail/Product" group-by="@type">
<Product>
<id>
<xsl:value-of select="@id"/>
</id>
<type>
<xsl:value-of select="@type"/>
</type>
<xsl:for-each select="current-group()">
<Dimension>
<lenght>
<xsl:value-of select="@lenght" />
</lenght>
<height>
<xsl:value-of select="@height" />
</height>
</Dimension>
</xsl:for-each>
</Product>
</xsl:for-each-group>
</ProductList>
</Detail>
</Envelope>
</xsl:message>
</xsl:template>
</xsl:stylesheet>



i changed some in my xslt.
im able to get the o/p now but the cust no is not displayed . Can you pls let me know where is the error

Case matters with XML names so instead of
you need to make sure you use the same case as the elements and attributes in the input XML have and there you have "Custno" attribute. Based on that I think you want

__________________
Martin Honnen
Microsoft MVP (XML, Data Platform Development) 2005/04 - 2013/03
My blog

Thanks Martin.
I overlooked that thanks for pointing it out