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Old October 25th, 2005, 06:26 PM
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Default Manipulating Processes ?

Here is a sample of my code.

using System;
using System.IO;
using System.Diagnostics;

namespace process

class Class1
public static string status = null;
public static string sfile = @"C:\kush\Tester\bin\debug\tester.exe";

static void Main(string[] args)

public static string launcher(string file)
Process p = null;

{ p = new Process();
p.StartInfo.FileName = file;
p.StartInfo.CreateNoWindow = false;
p.StartInfo.WindowStyle = ProcessWindowStyle.Normal;
//p.StartInfo.RedirectStandardOutput = true;
//p.StartInfo.UseShellExecute = false;
p.Start(); //status = p.StandardOutput.ReadToEnd(); p.WaitForExit();
catch (Exception ex)
Console.WriteLine("Exception Occured : {0}, {1}",ex.Message,ex.StackTrace.ToString());
return status;
using System;
using System.IO;
using System.Threading;

namespace tester
class Test
static void Main(string[] args)
When i run the program as above, it works fine. The parent process (Process.class1) calls the child process (Tester.test). In other words i can see both the parent and child process on the screen.

As soon as i uncomment the code below

p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.UseShellExecute = false;
status = p.StandardOutput.ReadToEnd

i can no longer see the child process when i run the parent process. Is there a way around in which i could still see the child process in action as well as capture any output given by the child process.


Old October 26th, 2005, 04:49 AM
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Why do you want to uncomment those lines, when you want to see the output?

I would suggest that you leave the three lines in the source and then save the status value when finished. This way you both see the output and save it.

Be aware that, if you are going to saave the standard error aswell you might have deadlock problems. I wrote another thread about this a some point.


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