Hi,

 I need to get the value from the first node and ignore the values from the next node.
I need to get just book1 and ignore book2, book3
<root>
<list>
 <item>book1</item>
 <item>book2</item>
  <item>book3</item>
</list>
</root>

I don't have a sample code to show you b'coz I don't have any ideas how to proceed on this... I tried to use preceding sibling, precedingnodes but of no use.....

You're trying to do grouping: read all about it at http://www.jenitennison.com/xslt/grouping

It's much easier in XSLT 2.0

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

I tried reading about grouping in xslt 2.0 as I'm using xslt 2.0;
I tried experimenting with the examples provided & some don't work (I'm using xslt 2.0 processor).....

None of them talk about grouping of the scenario I have......

Presently stuck with this.... and need some help!!!!!!!!

This is the xml file I have .I need to do work with this file in 2 ways.

1. To get only the first value and ignore the rest of the values.
get only BOOK1 AND BOOK3 from respective records.

2. To display the values together with a space between them; concatenate BOOK1 AND BOOK2 and display BOOK1 BOOK2 together which belong to the same record.

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <record>
        <item id="100">
            <book code="a">BOOK1</book>
        </item>
        <item id="100">
            <book code="a">BOOK2</book>
        </item>
    </record>
    <record>
        <item id="100">
            <book code="a">BOOK3</book>
        </item>
        <item id="100">
            <book code="a">BOOK4</book>
        </item>
    </record>
</root>

Sorry I misunderstood your requirement. You can get the first book in each record by writing (with a <record> as the context node):

select="item[1]/book"

You can display "BOOK1 BOOK2" (again with a <record> as the context node):

<xsl:value-of select="item/book"/>

For the latter make sure your stylesheet specifies version="2.0" otherwise you will get 1.0 mode which outputs only the first book.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

The solution you gave works only if we have the same id for all items.What if I want to get the values form other items too...
Using the below xslt I get COMPUTERS:P4 AND BOOK3

whereas the desired output is :
COMPUTERS:P4 LAPTOPS FOR RECORD1
BOOK3 CHAIRS FOR RECORD2
 I have my xslt below ; I know why it is giving me the above output but don't know how to fix this so that it can get me the desired output...


This is my XML:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="book.xsl"?>
<f:root xmlns:f="http://www.w3schools.com/furniture">
    <f:record>
        <f:item id="600">
            <f:book code="a">COMPUTERS:P4</f:book>
        </f:item>
        <f:item id="600">
            <f:book code="a">COMPUTERS:P3</f:book>
        </f:item>
          <f:item id="700">
            <f:book code="a">LAPTOPS</f:book>
        </f:item>

    </f:record>
    <f:record>
        <f:item id="100">
            <f:book code="a">BOOK3</f:book>
        </f:item>
        <f:item id="100">
            <f:book code="a">BOOK4</f:book>
        </f:item>
          <f:item id="700">
            <f:book code="a">CHAIRS</f:book>
        </f:item>
    </f:record>
</f:root>

---------------------------------------------------------
[b] This is my xslt [b]
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:f="http://www.w3schools.com/furniture">
        <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
 <xsl:template match="/">
        <xsl:for-each select="f:root/f:record">
            <xsl:for-each select="f:item[1]">
                <xsl:if test="@id=100">
                    <xsl:value-of select="."/> <br/>
                </xsl:if>
            </xsl:for-each>
            <xsl:for-each select="f:item[1]">
                <xsl:if test="@id=600">
                    <xsl:value-of select="."/> <br/>
                </xsl:if>
            </xsl:for-each>
            <xsl:for-each select="f:item[1]">
                <xsl:if test="@id=700">
                    <xsl:value-of select="."/> <br/>
                </xsl:if>
            </xsl:for-each>

        </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>

can someone please provide the solution to this...........

 can someone please provide the solution to this...........