The XSLT I'm working on is outputting to a flat text file (actually, it's a csv file). But I need to put line breaks at specific locations.

I know I'm forgetting something fundamental here, but I guess that's why I'm asking; I've forgotten.

I've tried setting a variable:

<xsl:variable name="nl" select="x0A/>

then using it

<xsl:value-of select="$nl"/>

or
<xsl:text>&amp;#0A;</xsl:text> (the forum sw is eating my ampersand)

but that is apparently not the right way to do it.

Any clues on where I can find the answer?

I'm using Saxon8, I've got XPath 2.0 and XSLT 2.0 as well as Worx's Professional XML. But I'm not locating the solution.

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GnuPG Key fingerprint = 1AD4 726D E359 A31D 05BF ACE5 CA93 7AD5 D8E3 A876

Michael Hare

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GnuPG Key fingerprint = 1AD4 726D E359 A31D 05BF ACE5 CA93 7AD5 D8E3 A876

Michael Hare

Nevermind, I was missong the 'x'

<xsl:text>&amp;#x0A;</xsl:text>

works.




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GnuPG Key fingerprint = 1AD4 726D E359 A31D 05BF ACE5 CA93 7AD5 D8E3 A876

Michael Hare

Use <xsl:output method="text"/>, and then use

<xsl:text>#x0a;</xsl:text>

to output the newline.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

That should read

ampersand hash x 0 a semicolon.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference