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Old March 2nd, 2007, 07:50 AM
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Default getting the parent

I am in one node i want to get it's parent ....and the parent of this parent

for example
<root>
   <node1>
      <child1>
            <mynode>
     </child1>
   </node1>
</root>

i'm in mynode....now first i want to get child1..then i will do something and from child1 i want to go node1....

but this going will by dynamically nut specifying the path with node name...like node1/child1 directly..
how to do that?


 
Old March 2nd, 2007, 08:27 AM
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.. fetches the parent.

--

Joe (Microsoft MVP - XML)
 
Old March 2nd, 2007, 08:38 AM
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Asking this question on a forum seems to be a very inefficient way of getting basic information. What reference book are you using, and isn't the information in the index under "parent"?

The expression ".." returns the parent of the context node.

Michael Kay
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Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
 
Old March 3rd, 2007, 12:52 AM
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<xsl:template name = "checkPosition1" match ="/node()">
    <xsl:template match ="/node()">
    <xsl:choose>
            <xsl:when test="position()=last()">
                <img class="hiericon" src="images/blank.png"/>
            </xsl:when>
            <xsl:otherwise>
                <img class="hiericon" src="images/I.png"/>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>
</xsl:template>


actulally i want to check if the parent is the last position if so i want to put my image...to do that i have written that template that will check 2nd level parent of the corrent node..

and my node structure is like that...
<parent1>
<parent2>
<parent3>
     <ch1>
          <nod1>
          <nod2>
     <ch2>
          <node1>
          <node2>

here parent3 is in the last position and from node1 or node2 i want to check parent3 is in the last or not if in last then i will put blank image and if not then i will put I image..

but it's not working..i'have tried with '..' also but giving some syntax error...i think my template stucture is worng..xslt 1.0 i'm using

 
Old March 3rd, 2007, 01:27 AM
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I have tried like this also..

<xsl:template name = "checkPosition1" match ="/node()">
 <xsl:for-each select="..">
    <xsl:for-each select="..">
    <xsl:choose>
            <xsl:when test="position()=last()">
                <img class="hiericon" src="images/blank.png"/>
                            </xsl:when>
            <xsl:otherwise>
                <img class="hiericon" src="images/I.png"/>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:for-each>
    </xsl:for-each>
</xsl:template>

here i can get the 2nd level aprent but it always satisfying the position()=last()

i'm not getting why ..

 
Old March 3rd, 2007, 04:31 AM
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You wrote:

 <xsl:template name = "checkPosition1" match ="/node()">
    <xsl:template match ="/node()">

You can't have one template inside another - I don't know what you would expect it to mean. match="/node()" matches any node that is a direct child of the document root - I don't know what you expected that to achieve either.

The construct

<xsl:when test="position()=last()">

does not test the position of a node in the source tree, it tests its position in the current sequence of nodes being processed. Sometimes that's the same thing, but not in this case, because you aren't processing nodes in tree order. In particular when you do it within

<xsl:for-each select="..">

the current node list contains a single node (the parent), so position() and last() are both equal to 1.

>i want to check if the parent is the last position

that's test="not(../following-sibling::*)"



Michael Kay
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Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
 
Old March 3rd, 2007, 04:58 AM
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thnx for reply..so the problem with my template stucture..can pls help me with the syntax how to get the 2nd level parent position
 
Old March 3rd, 2007, 10:25 AM
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>but this going will by dynamically nut specifying the path with node name...like node1/child1 directly.. how to do that?

I don't understand your question. Please try to express yourself more clearly. In fact, please read your sentences before hitting send, and ask yourself whether they make sense.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference




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